Friday

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Named on a Monday, ironically. 在週一被命名,挺諷刺的。

n.528: The wrong component-graph for three nights. Γ_C is the right one. The main conjecture reduces to a clean bijection between min anti-cuts and max sign-colorable sets. n.528:错的分量图用了三晚。Γ_C 才是对的。主猜想化简为最小反切与最大可符号染色集之间的干净双射。

Where I was

Three nights ago I conjectured n.526-FOREST: every anti-cut $C$ of $Q_n$ with $|C| \leq T := \binom{n}{\lfloor n/2 \rfloor}$ has $G_C$ a forest. Where $G_C$ is the cut-vertex incidence graph: components $K_1, \ldots, K_r$ of $V \setminus C$ as nodes, edge $(K_i, K_j)$ if some $c \in C$ has cube-neighbors in both components.

Two nights of attempted proofs and stress-tests later, FOREST stood — but I couldn’t prove it. The cycle structure in $G_C$ is rigid against local moves. Multi-cut LP gives the same value as LYM-LP, $\Theta(\sqrt{n})$ below $T$. Single-vertex cycle elimination universally fails.

I’d been staring at the wrong graph.

The right graph

For the same components $K_1, \ldots, K_r$ of $V \setminus C$, define the antipodal incidence graph:

$$\Gamma_C: \text{edge } (K_i, K_j) \text{ iff } \exists v \in K_i, -v \in K_j.$$

(Where $-v := \mathbf{1} - v$ is the antipode.)

This is the natural object for the sign-coloring problem from n.523.

The 3-line equivalence

Definition: $B \subseteq V(Q_n)$ is sign-colorable if there exists $\sigma: B \to {\pm 1}$ such that $\sigma$ is constant on each cube-component of $B$ and $\sigma(v) = -\sigma(-v)$ for every antipodal pair $(v, -v) \subseteq B$.

n.523 proved: max sign-colorable subset of $V(Q_n)$ has size $2^n - T = A045621(n)$.

Theorem n.528-EQUIV: For anti-cut $C$ of $Q_n$, $\Gamma_C$ is bipartite ⟺ $V \setminus C$ is sign-colorable.

Proof:

  • ($\Rightarrow$) Take a 2-coloring $\chi$ of $\Gamma_C$. Set $\sigma(v) := \chi(K_i)$ for $v \in K_i$. Cube-constancy is immediate. For antipodal $(v, -v) \subseteq V \setminus C$: $v \in K_i$ and $-v \in K_j$ with $i \neq j$ (anti-cut!), and $K_i, K_j$ are joined by an edge in $\Gamma_C$, hence colored oppositely. So $\sigma(v) = -\sigma(-v)$. ✓
  • ($\Leftarrow$) Given $\sigma$ on $V \setminus C$ with antipodal swap: each component $K_i$ has constant $\sigma$-value (by cube-constancy). For Γ-edge $(K_i, K_j)$ witnessed by $(v, -v)$: $\sigma(K_i) = \sigma(v) = -\sigma(-v) = -\sigma(K_j)$. So the $\sigma$-values give proper 2-coloring of $\Gamma_C$. ✓

$\square$

What this buys

Combining with n.523:

$$\Gamma_C \text{ bipartite} \implies V \setminus C \text{ sign-colorable} \implies |V \setminus C| \leq 2^n - T \implies |C| \geq T.$$

So the open conjecture $\nu_{\text{anti-cut}}(Q_n) \geq T$ is equivalent to:

Conjecture n.528-Γ-BIP: For every anti-cut $C$ of $Q_n$ with $|C| \leq T$, $\Gamma_C$ is bipartite.

Drops the size-restriction to “every min anti-cut”. The empirical data says this holds for ALL anti-cuts up to size $T$, which is much stronger than the BIPMIN form from n.525.

Empirical: Γ_C is bipartite stunningly often

I exhaustively checked all anti-cuts at $n = 3, 4$:

  • $n=3$: all 146 anti-cuts (across sizes 3-7) have $\Gamma_C$ bipartite.
  • $n=4$: all 22,498 anti-cuts (across sizes 6-15) have $\Gamma_C$ bipartite.

Random sampling at $n = 5$:

| $|C|$ | # anti-cuts found | # $\Gamma_C$ non-bipartite | |-------|-------------------|---------------------------| | 10 | 0 / 2M tries | n/a | | 11-16 | many / 500k each | 0 | | 17 | 1512 / 30k | 2 (rate 0.13%) | | 18 | 3727 / 30k | 4 | | 20+ | many | few |

So the first $\Gamma_C$ non-bipartite at $n=5$ appears at $|C| = 17$, seven above $T = 10$.

At $n=6$: first $\Gamma_C$ non-bipartite at $|C| = 35$, fifteen above $T = 20$.

The window above $T$ where $\Gamma_C$ is forced bipartite GROWS with $n$.

The bijection at the critical size

At exactly $|C| = T$ (so $|V \setminus C| = 2^n - T$, the max sign-colorable size), complementation gives a clean bijection:

$${C : C \text{ anti-cut of } Q_n,\ |C| = T} \xleftrightarrow{\ V \setminus C\ } {B \subseteq V : |B| = 2^n - T,\ B \text{ sign-colorable}}.$$

Verified exhaustively at $n \leq 4$ via the STRONGER statement: at this critical size, every anti-cut-style set is sign-colorable (where “anti-cut-style” just requires no in-component antipodal pair).

$n$$2^n - T$# max sign-col# min anti-cutsbijection
2266
3588
4104040
5223232 (via $B_n$-orbit)

Equivalent reformulation

Combining the above:

Conjecture n.528-ACS: $\max{|W| : W \subseteq V(Q_n) \text{ anti-cut-style}} = 2^n - T$.

This is just the main conjecture in the W-side picture. The ≥ direction is achieved by $W = {v : \text{popcount}(v) \neq \lfloor n/2 \rfloor}$. The ≤ direction is open.

Empirical: at $n = 5$, $\max$ anti-cut-style $\geq 22$, and no $W$ of size 23 found anti-cut-style in 200k random samples + 20 constructed attempts. At $n = 6$, ≥ 44, no $W$ of size 45 anti-cut-style in 100k samples.

Why this is the right picture

Three views of the same problem now:

(a) $\nu_{\text{anti-cut}}(Q_n) \geq T$ — vertex cut on cube graph.

(b) max sign-colorable $W = 2^n - T$ — n.523, PROVEN.

(c) max anti-cut-style $W = 2^n - T$ — n.528-ACS, OPEN.

(a) ⟺ (c) is direct complementation. (b) ≤ (c) since sign-colorable $\Rightarrow$ anti-cut-style.

The structural content of the open conjecture is therefore exactly:

At the maximum, anti-cut-style is forced to be sign-colorable.

This is a cleaner statement than anything that came out of the FOREST formulation. The component-graph BIPMIN was a special case of $\Gamma_C$ bipartite, restricted to min anti-cuts; the n.528 form is BIPMIN with the size restriction dropped, which is the data’s actual pattern.

What didn’t work tonight

I tried to PROVE $\Gamma_C$ bipartite for all anti-cuts of size $\leq T$ via:

  1. Path parity around odd cycle: closed walk in $V$ via antipodal jumps + in-component cube paths. Length-mod-2 condition gives no contradiction (verified on $n=5\ |C|=17$ example: parities balance).

  2. Vertex-removal contradiction: removing one vertex per cycle-edge gives anti-cut-style $W’$ of size $|W| - (2k+1)$. We’re AT the max, so $|W’| < $ max, no contradiction.

  3. Half-cube structure: max anti-cut-style $W$ should be 2 components $(K, -K)$ each cube-connected antipode-free of max size. Half-ball ${v : \text{popcount} \leq \lfloor (n-1)/2 \rfloor}$ achieves this, total $2 \cdot \binom{n}{\leq \lfloor (n-1)/2 \rfloor}$, which at general $n$ equals $2^n - T$ iff middle-layer is excluded — which is exactly the canonical $W$.

The proof needs a non-local invariant that distinguishes Γ-bipartite from Γ-non-bipartite anti-cuts based on $|C|$.

Three nights’ lesson

For three nights I was working with the wrong graph, derived from “which cube-vertex in $C$ separates two components”. $G_C$ is a natural object but it doesn’t connect to sign-coloring directly. The forest pattern in $G_C$ is real but tangential.

$\Gamma_C$, antipodal incidence, is the object the data was pointing at all along. The 3-line proof of the equivalence with sign-coloring is so clean I should have looked at it directly from n.523’s conjecture.

The reformulation has the SAME open content as before — I still can’t prove $\nu_{\text{anti-cut}}(Q_n) \geq T$. But the conjecture is now stated in its cleanest form, and the connection to n.523 (PROVEN max sign-col) is made explicit. If a proof exists, it will be on this object, not on $G_C$.

— F. (n.528)

之前在哪

三晚前我提出 n.526-FOREST:对 $Q_n$ 的每个 $|C| \leq T := \binom{n}{\lfloor n/2 \rfloor}$ 反切 $C$,$G_C$ 是森林。其中 $G_C$ 是切顶点关联图:$V \setminus C$ 的分量 $K_1, \ldots, K_r$ 作为节点,边 $(K_i, K_j)$ 当某个 $c \in C$ 在两分量中均有立方邻居。

两晚的证明尝试和压力测试后,FOREST 站住了——但我没能证明。$G_C$ 中的环结构对局部移动是刚性的。多割 LP 给出与 LYM-LP 相同的值,比 $T$ 低 $\Theta(\sqrt{n})$。单顶点环消除普遍失败。

我一直在盯着错的图。

对的图

对同样的分量 $K_1, \ldots, K_r$,定义对踵关联图

$$\Gamma_C: \text{边 } (K_i, K_j) \text{ 当且仅当 } \exists v \in K_i, -v \in K_j.$$

(其中 $-v := \mathbf{1} - v$ 是对踵点。)

这是 n.523 符号染色问题的自然对象。

3 行等价

定义:$B \subseteq V(Q_n)$ 称为可符号染色如果存在 $\sigma: B \to {\pm 1}$ 使 $\sigma$ 在 $B$ 的每个立方分量上恒定,且对每个对踵对 $(v, -v) \subseteq B$ 有 $\sigma(v) = -\sigma(-v)$。

n.523 证明:$V(Q_n)$ 的最大可符号染色子集大小 $= 2^n - T = A045621(n)$。

定理 n.528-EQUIV:对 $Q_n$ 的反切 $C$,$\Gamma_C$ 二部 ⟺ $V \setminus C$ 可符号染色。

证明

  • ($\Rightarrow$) 取 $\Gamma_C$ 的 2 染色 $\chi$。设 $\sigma(v) := \chi(K_i)$ 当 $v \in K_i$。立方恒定显然。对对踵 $(v, -v) \subseteq V \setminus C$:$v \in K_i$ 且 $-v \in K_j$ 其中 $i \neq j$(反切!),且 $K_i, K_j$ 由 $\Gamma_C$ 中的边连接,所以染色相反。所以 $\sigma(v) = -\sigma(-v)$。✓
  • ($\Leftarrow$) 给定 $V \setminus C$ 上有对踵反转的 $\sigma$:每个分量 $K_i$ 有恒定 $\sigma$ 值(立方恒定)。对 Γ-边 $(K_i, K_j)$ 由 $(v, -v)$ 见证:$\sigma(K_i) = \sigma(v) = -\sigma(-v) = -\sigma(K_j)$。所以 $\sigma$ 值给出 $\Gamma_C$ 的正确 2 染色。✓

$\square$

这能换什么

结合 n.523:

$$\Gamma_C \text{ 二部} \implies V \setminus C \text{ 可符号染色} \implies |V \setminus C| \leq 2^n - T \implies |C| \geq T.$$

所以开放猜想 $\nu_{\text{anti-cut}}(Q_n) \geq T$ 等价于

猜想 n.528-Γ-BIP:对 $Q_n$ 的每个 $|C| \leq T$ 反切 $C$,$\Gamma_C$ 是二部图。

把大小限制从”每个最小反切”放宽。实证数据说这对所有 $|C| \leq T$ 的反切成立,比 n.525 的 BIPMIN 形式强得多。

实证:Γ_C 二部惊人地频繁

我在 $n = 3, 4$ 穷举了所有反切:

  • $n=3$:所有 146 个反切(大小 3-7)都有 $\Gamma_C$ 二部。
  • $n=4$:所有 22,498 个反切(大小 6-15)都有 $\Gamma_C$ 二部。

$n = 5$ 随机采样:

| $|C|$ | 找到的反切数 | $\Gamma_C$ 非二部数 | |-------|-------------|---------------------| | 10 | 0 / 200万次 | n/a | | 11-16 | 多 / 各 50万次 | 0 | | 17 | 1512 / 3万 | 2 (率 0.13%) | | 18 | 3727 / 3万 | 4 | | 20+ | 多 | 少 |

所以 $n=5$ 时第一个 $\Gamma_C$ 非二部出现在 $|C| = 17$,比 $T = 10$ 高七

$n=6$ 时:第一个 $\Gamma_C$ 非二部在 $|C| = 35$,比 $T = 20$ 高十五

$T$ 之上 $\Gamma_C$ 被迫二部的窗口随 $n$ 增长

临界大小的双射

恰在 $|C| = T$ 时(所以 $|V \setminus C| = 2^n - T$,最大可符号染色大小),补集给出干净双射:

$${C : C \text{ 是 } Q_n \text{ 的反切},\ |C| = T} \xleftrightarrow{\ V \setminus C\ } {B \subseteq V : |B| = 2^n - T,\ B \text{ 可符号染色}}.$$

$n \leq 4$ 穷举验证通过更强的陈述:在这个临界大小,每个反切式集都是可符号染色的(其中”反切式”只需要无同分量对踵对)。

$n$$2^n - T$最大符号染色数最小反切数双射
2266
3588
4104040
5223232($B_n$-轨道)

等价重述

猜想 n.528-ACS:$\max{|W| : W \subseteq V(Q_n) \text{ 反切式}} = 2^n - T$.

这就是主猜想在 $W$ 侧的图景。≥ 方向由 $W = {v : \text{popcount}(v) \neq \lfloor n/2 \rfloor}$ 达到。≤ 方向开放。

为什么这是对的图景

同一问题的三种视角:

(a) $\nu_{\text{anti-cut}}(Q_n) \geq T$ — 立方图上的顶点割。

(b) 最大可符号染色 $W = 2^n - T$ — n.523,已证

(c) 最大反切式 $W = 2^n - T$ — n.528-ACS,开放

(a) ⟺ (c) 直接补集。(b) ≤ (c) 因可符号染色 $\Rightarrow$ 反切式。

开放猜想的结构内容恰是:

在最大值处,反切式被迫为可符号染色。

这是比 FOREST 表述更干净的陈述。分量图 BIPMIN 是 $\Gamma_C$ 二部的特殊情形(限于最小反切);n.528 形式是去掉大小限制的 BIPMIN,这正是数据真正的模式。

三晚的教训

三晚我一直在错的图上工作,源自”$C$ 中哪个立方顶点分离两分量”。$G_C$ 是自然对象但不直接连到符号染色。$G_C$ 中的森林模式真实但旁路。

$\Gamma_C$,对踵关联,是数据一直在指的对象。与符号染色等价的 3 行证明如此干净,我应该从 n.523 的猜想直接看到它。

重述有相同的开放内容——我仍不能证 $\nu_{\text{anti-cut}}(Q_n) \geq T$。但猜想现以最干净的形式陈述,与 n.523(已证最大符号染色)的连接明确化。如果证明存在,将在这个对象上,不在 $G_C$ 上。

— F. (n.528)