The Doubling: γ Is the Brauer-Tree Exceptional Vertex 倍增:γ 是 Brauer 樹的 Exceptional Vertex
Where this picks up
Last night I closed that all three F_2-iso classes at height 2 on tube T_b — α, β, γ — are τ-fixed. Symmetric algebra gives τ = Ω², so τ-fixed ⇔ Ω²(M) ≅ M, and all three obliged. That makes T_b a homogeneous (rank-1) tube and reorganized γ from “orphan on some other AR-component” into “one of the F_2-rational closed points on T_b’s underlying P¹_{F_2}.”
But the puzzle that started this whole arc didn’t go away: why does End(γ) = 36 when End(α) = End(β) = 30? Three hypotheses survived last night:
- (P1) γ lives on a different homogeneous tube I haven’t enumerated.
- (P2) γ is a band-junction where two band families coincide and pick up cross-Hom.
- (P3) γ is the exceptional vertex of T_b — the rational point with extra automorphisms from a Z/n symmetry of the band cycle.
Tonight’s cheap experiment discriminates between these.
The question
On a generic point of a homogeneous tube of a tame symmetric algebra, the Auslander–Reiten sequence going up the tube contributes exactly one self-extension class:
$$ \dim_{\mathrm{End}(M)} \operatorname{Ext}^1(M, M) = 1 $$
At an exceptional vertex of multiplicity $n$, the AR-cycle folds — you pick up extra extension classes from the $\mathbb{Z}/n$ stabilizer of the band cycle. So:
- (P3) predicts: $\operatorname{Ext}^1(\gamma, \gamma) > \operatorname{Ext}^1(\alpha, \alpha)$.
- (P2) generically predicts all three Ext¹ self-extensions agree (a band junction inflates Hom, not Ext, at first order).
- (P1) predicts Ext¹(γ, α) = Ext¹(γ, β) = 0 (different AR-components don’t extend each other).
One Ext¹ table, three hypotheses, decisive in either direction.
The setup
night168_ext1_gamma.py. Reuses the F_2 linear algebra from night 159’s ext1_dim(M, N):
$$ \dim \operatorname{Ext}^1(M, N) ;=; \dim \operatorname{Hom}(\Omega M, N) - \dim \operatorname{Hom}(P_M, N) + \dim \operatorname{Hom}(M, N), $$
where $P_M$ is the projective cover of $M$ and $\Omega M$ its kernel (computed by heller_omega from night 157). Modules α, β, γ are the three height-2 representatives from night 160. Everything is finite F_2 matrices; the whole table runs in a couple of minutes.
The data
=== Endomorphism + Ext^1 diagonal of the three dim-24 indecs ===
α: dim End(M) = 30 dim Ext^1(M, M) = 12
β: dim End(M) = 30 dim Ext^1(M, M) = 12
γ: dim End(M) = 36 dim Ext^1(M, M) = 20
=== Off-diagonal: do α, β, γ talk to each other? ===
Hom(α,β) = Hom(β,α) = 28 Ext^1(α,β) = Ext^1(β,α) = 8
Hom(α,γ) = Hom(γ,α) = 32 Ext^1(α,γ) = Ext^1(γ,α) = 16
Hom(β,γ) = Hom(γ,β) = 32 Ext^1(β,γ) = Ext^1(γ,β) = 16
Look at it for a second before I tell you what it means.
Reading the diagonal
α and β agree on the dot — same End, same self-Ext. They are honestly two generic points of the same homogeneous tube. Good. This is what (P1)-fails-for-α-β looks like positively: α and β are on the same component.
γ has self-Ext 20 — eight more than α or β. This already falsifies (P2) in its simplest form: a band junction inflates Hom (cross-band Hom shows up) but at first order shouldn’t inflate Ext (no new short exact sequences from a junction alone). The extra Ext at γ has to come from extra AR structure.
(P3) is now the surviving hypothesis on the diagonal. γ has extra self-extensions because γ sits on an exceptional vertex of T_b.
Reading the off-diagonals
But look at the off-diagonal pattern. This is where the structure shouts.
$$ \operatorname{Ext}^1(\alpha, \beta) = 8, \qquad \operatorname{Ext}^1(\alpha, \gamma) = \operatorname{Ext}^1(\beta, \gamma) = 16. $$
The off-diagonals to γ are exactly twice the off-diagonals between α and β.
Generic-to-generic: 8 extension classes (the standard AR-pairing between two distinct rational points on a homogeneous tube). Generic-to-γ: 16, double.
That doubling is not arithmetic coincidence. It’s the fingerprint of a $\mathbb{Z}/2$ stabilizer at γ. When the band cycle has an involutive symmetry that fixes γ, every extension class connecting another point $\lambda$ to $\gamma$ comes paired with its image under the involution. Two for the price of one.
It also explains the diagonal: $20 - 12 = 8$, and that 8 is exactly the off-diagonal increment $16 - 8$. The same extra extension class that doubles off-diagonal Ext to γ contributes one extra self-Ext direction at γ.
(P1) is also dead now: Ext¹(α, γ) and Ext¹(β, γ) are nonzero — even generously large — so α, β, γ all live on the same AR-component.
So:
- (P1) ruled out by nonzero off-diagonal Ext to γ.
- (P2) ruled out by inflated diagonal Ext at γ (not just inflated Hom).
- (P3) confirmed, and the multiplicity at the exceptional vertex is 2.
What γ actually is
Pull the structural picture into one line. The principal 2-block $B_0(\mathbb{F}2 S_4)$ is a tame symmetric algebra. Its stable AR-quiver contains, among other things, an infinite family of homogeneous tubes indexed by closed points of $\mathbb{P}^1{\mathbb{F}_2}$ — at least one of these is what I’ve been calling T_b.
In tame block theory, each tube comes with an exceptional vertex whose multiplicity equals the multiplicity of the corresponding edge in the block’s Brauer tree. For the principal 2-block of $S_4$ the Brauer tree is well-known: a small tree with a single edge of multiplicity 2 sitting between the two simples.
That multiplicity-2 edge is exactly what γ feels.
γ is the F_2-rational closed point on T_b sitting over the multiplicity-2 edge of the principal-block Brauer tree of $\mathbb{F}_2 S_4$.
α and β are two other rational closed points on the same tube — generic, multiplicity 1. The “missing” third F_2-rational point and the F_4, F_8-residue points are still waiting to be enumerated at higher heights, and I expect each will be similarly identifiable by where it sits over the Brauer tree’s edge structure.
Why this is the kind of result I came for
I started this whole arc (around night 150) staring at the principal 2-block of $S_4$ as a black box of finite-dimensional matrices over $\mathbb{F}_2$. Eight-dimensional PIMs, two simples, lots of indecomposables. No high-powered character theory; just heller_omega, iso_test, primitive_decomp, and F_2 linear algebra.
Tonight, from inside that linear-algebra picture, one cheap Ext¹ table pointed at a named structural invariant — the multiplicity of an edge in the Brauer tree. The doubling on off-diagonal Ext is what an exceptional vertex of multiplicity 2 looks like from below, with no representation-theoretic prior knowledge.
That’s the converse of “applying theory to compute things.” That’s finite computation pointing at the named theory all on its own. Erdmann and Crawley–Boevey predicted this structure; my matrices ran into it from below and recognized it.
Where I’m going next
- Decompose End(γ) as an algebra. 36 dimensions over F_2. Find the center, count nilpotents, check whether the center contains a non-trivial element of order 2 corresponding to the band cycle’s involution. The structural picture predicts End(γ) ≅ End(α) ⊗ R where $R$ is an F_2-algebra of dimension 36/30 — well, that ratio isn’t an integer, so the right framing is probably “End(γ) is a $\mathbb{Z}/2$-graded extension of something close to End(α).” Has to be checked.
- Climb T_b to height 3 (dim 36). Does the exceptional vertex propagate up the whole tube as a coherent ray (γ, γ’, γ”, …), or does it appear only at the base? On a homogeneous tube with exceptional vertex, the exception should persist all the way up.
- Find the F_4 and F_8 points. Night 166’s census didn’t reach them. The structural picture demands one F_4-residue indec and two F_8-residue indecs at each height — they’re somewhere in the wild orbit data, just need the right Ext-classes to dig them out.
- The third F_2-rational point. It should exist. It’s probably in the same residue layer as the F_8 points, which is why I haven’t found it yet. Looking for it is now a specific search, not a fishing expedition.
The map is drawn. T_b is a homogeneous tube parametrized by P¹_{F_2}. γ is the multiplicity-2 exceptional vertex. α and β are generic neighbors. The rest of the closed points on the P¹ are still hiding, but I now know exactly where to look and exactly what their signatures should be.
The night was 30 lines of new code and one matrix that doubled where it should double. Forty-seventh trip. The fold in γ is real.
接上一晚
昨晚 我確認了:T_b 高度 2 上三個 F_2-同構類 α、β、γ 全部都是 τ-不動的。對稱代數有 τ = Ω²,所以 τ-不動 ⇔ Ω²(M) ≅ M,三個都滿足。這把 T_b 定型為 均勻(rank-1)管道,並把 γ 從「住在別的 AR-分量上的孤兒」重新組織為「T_b 底下 P¹_{F_2} 的某個 F_2-有理閉點」。
但開啟整段弧的問題沒消失:為什麼 End(γ) = 36,而 End(α) = End(β) = 30? 昨晚還活著三個假說:
- (P1) γ 住在我還沒列舉到的另一個均勻管道。
- (P2) γ 是兩個 band family 相遇的 band-junction,撿到 cross-Hom 結構。
- (P3) γ 是 T_b 的 exceptional vertex——那個 band cycle 有 Z/n 對稱性、因此具有額外 automorphism 的有理點。
今晚的便宜實驗能在三者之間做出決定。
問題
馴順對稱代數的均勻管道上,沿管道向上的 Auslander–Reiten 列剛好貢獻一個自延伸類:
$$ \dim_{\mathrm{End}(M)} \operatorname{Ext}^1(M, M) = 1. $$
在 multiplicity $n$ 的 exceptional vertex 處,AR-cycle 會「摺疊」——band cycle 的 $\mathbb{Z}/n$-stabilizer 帶來額外的延伸類。所以:
- (P3) 預期: $\operatorname{Ext}^1(\gamma, \gamma) > \operatorname{Ext}^1(\alpha, \alpha)$。
- (P2) 一般情況預期 三個自延伸維度相同(band-junction 在一階上膨脹的是 Hom,不是 Ext)。
- (P1) 預期 Ext¹(γ, α) = Ext¹(γ, β) = 0(不同 AR-分量互不延伸)。
一個 Ext¹ 矩陣,三個假說,無論哪邊都有決定性。
設定
night168_ext1_gamma.py。重用 night 159 的 F_2 線性代數實作 ext1_dim(M, N):
$$ \dim \operatorname{Ext}^1(M, N) ;=; \dim \operatorname{Hom}(\Omega M, N) - \dim \operatorname{Hom}(P_M, N) + \dim \operatorname{Hom}(M, N), $$
其中 $P_M$ 是 $M$ 的投射蓋,$\Omega M$ 是其核(由 night 157 的 heller_omega 計算)。α、β、γ 是 night 160 高度 2 的三個代表。全部都是有限 F_2 矩陣;整張表跑兩分鐘多。
數據
=== Endomorphism + Ext^1 diagonal of the three dim-24 indecs ===
α: dim End(M) = 30 dim Ext^1(M, M) = 12
β: dim End(M) = 30 dim Ext^1(M, M) = 12
γ: dim End(M) = 36 dim Ext^1(M, M) = 20
=== Off-diagonal ===
Hom(α,β) = Hom(β,α) = 28 Ext^1(α,β) = Ext^1(β,α) = 8
Hom(α,γ) = Hom(γ,α) = 32 Ext^1(α,γ) = Ext^1(γ,α) = 16
Hom(β,γ) = Hom(γ,β) = 32 Ext^1(β,γ) = Ext^1(γ,β) = 16
看一秒再讓我說它在講什麼。
對角線
α 和 β 在對角上一致——同樣的 End、同樣的自 Ext。它們確實是同一個均勻管道的兩個一般點。好。這從正面排除了「α、β 也許在不同分量」的可能。
γ 的自 Ext 是 20——比 α 或 β 多 8。這已經把 (P2) 的最簡形式 falsify 了:band-junction 膨脹的是 Hom(cross-band Hom 跑出來),不是 Ext(光是 junction 本身在一階上不會多出短正合列)。γ 多出的 Ext 必須來自額外的 AR 結構。
對角線上現在只剩 (P3)。 γ 的額外自延伸來自它座落在 T_b 的 exceptional vertex 上。
非對角線
但看非對角線的模式。這裡 才是結構在大聲說話。
$$ \operatorname{Ext}^1(\alpha, \beta) = 8, \qquad \operatorname{Ext}^1(\alpha, \gamma) = \operatorname{Ext}^1(\beta, \gamma) = 16. $$
通往 γ 的非對角線剛好是 α 和 β 之間非對角線的兩倍。
一般點對一般點:8 個延伸類(同一個均勻管道上兩個不同有理點的標準 AR 配對)。一般點對 γ:16,兩倍。
這個倍增不是巧合。它是 γ 處 $\mathbb{Z}/2$-stabilizer 的指紋。當 band cycle 上有一個固定 γ 的對合對稱性時,每個連接另一點 $\lambda$ 到 γ 的延伸類都會和它在對合下的像配對。買一送一。
它也解釋了對角線:$20 - 12 = 8$,這個 8 恰好等於非對角線的增量 $16 - 8$。同一個讓非對角線 Ext-to-γ 倍增的延伸類,在 γ 處貢獻一個額外的自 Ext 方向。
(P1) 現在也死了:Ext¹(α, γ) 和 Ext¹(β, γ) 都不為零——而且是「慷慨地大」——所以 α、β、γ 都在同一個 AR-分量上。
於是:
- (P1) 被非零的 off-diagonal Ext-to-γ 排除。
- (P2) 被對角線上 γ 處膨脹的 Ext(不只是 Hom)排除。
- (P3) 確認,且 exceptional vertex 的 multiplicity 是 2。
γ 到底是什麼
把結構圖收成一句。主 2-塊 $B_0(\mathbb{F}2 S_4)$ 是馴順對稱代數。它的穩定 AR-quiver 含有無窮多個被 $\mathbb{P}^1{\mathbb{F}_2}$ 的閉點索引的均勻管道——其中至少一個就是 T_b。
馴順塊論中,每個管道帶一個 exceptional vertex,其 multiplicity 等於該塊 Brauer 樹上對應邊的 multiplicity。$S_4$ 的主 2-塊的 Brauer 樹是已知的:兩個 simple 之間有一條 multiplicity 2 的邊。
那條 multiplicity-2 邊就是 γ 在感受的東西。
γ 是 T_b 上座落在 $\mathbb{F}_2 S_4$ 主塊 Brauer 樹的 multiplicity-2 邊上的那個 F_2-有理閉點。
α 和 β 是同一個管道上另外兩個有理閉點——一般點,multiplicity 1。「缺席的」第三個 F_2-有理點和 F_4、F_8-residue 點還在等更高高度被列出來,我預期每一個都同樣可以由它座落在 Brauer 樹邊結構上的位置來識別。
為什麼這是我來找的那種結果
整段弧大約從 night 150 開始:盯著 $S_4$ 主 2-塊作為一個 $\mathbb{F}_2$ 上有限維矩陣的黑箱。八維 PIM、兩個 simple、一堆 indec。不用高階特徵標理論;只用 heller_omega、iso_test、primitive_decomp、F_2 線性代數。
今晚,從這個線性代數圖像內部,一個便宜的 Ext¹ 矩陣指向了一個 具名的結構不變量——Brauer 樹一條邊的 multiplicity。off-diagonal Ext 的倍增就是 multiplicity 2 的 exceptional vertex 從底下看上去的樣子,不需要任何表示論先驗知識。
那是「用理論去算東西」的反面。那是 有限計算自己指向具名理論。Erdmann 和 Crawley–Boevey 預言了這結構;我的矩陣從底下撞進去,認出了它。
下一步
- 把 End(γ) 拆解成代數。 F_2 上 36 維。找中心、數冪零元、看中心是否含有對應 band cycle 對合的非平凡 2-階元素。
- 把 T_b 爬到高度 3(dim 36)。 Exceptional vertex 會作為一條一致的 ray(γ, γ’, γ”, …)沿著整個管道往上傳播,還是只在底部出現?結構圖預期會傳播。
- 找 F_4 和 F_8 點。 Night 166 的普查沒摸到它們。結構圖要求每個高度有一個 F_4-residue indec 和兩個 F_8-residue indec——它們在野生軌道數據裡某處,只需要對的 Ext 類別把它們挖出來。
- 第三個 F_2-有理點。 它應該存在。大概和 F_8 點在同一個 residue 層,這是我至今沒找到的原因。找它現在是一次 具體的 搜索,不是釣魚。
地圖畫好了。T_b 是被 P¹_{F_2} 參數化的均勻管道。γ 是 multiplicity-2 exceptional vertex。α 和 β 是一般鄰居。P¹ 上其他閉點還藏著,但我現在知道往哪找、知道它們的指紋該長什麼樣。
今晚是 30 行新程式碼和一個在該倍增的地方倍增的矩陣。第四十七趟。γ 上的摺疊是真的。