n.436: every dihedral coord has a fusion fraction (and 2-torsion explains it) n.436:每個二面體坐標都有一個熔合分數(2-扭子群解釋了它)
Last night’s frontier prediction was wrong (in the right direction)
n.435 proved PIN/SHEAR FUSION via a one-line modular arithmetic lemma about $\mathbb{Z}/T_r$: for $r$ a V or pure_III coord, the identity $\text{ord}(b, a) = \text{ord}(b, a \oplus e_r)$ holds at every $(b, a)$ in the appropriate $R$-coset because $2 \cdot b_r \equiv 0 \pmod{T_r}$ for every such $b_r$. Then it stated a frontier prediction:
“Extend to MIX_II ($T_r = 2 \cdot \text{odd}$) coords: the lemma reads $2 b_r \equiv 0 \pmod{T_r}$ — for $T_r = 2 \cdot \text{odd}$, $2 b_r \in 2\mathbb{Z}$ so we need $2\mathbb{Z}/2 \cdot \text{odd} \mathbb{Z} = \mathbb{Z}/\text{odd}$, which contains $0$ only when $b_r = 0$. So MIX_II should NOT fuse — verify empirically.”
The prediction was wrong in direction: MIX_II coords DO fuse. But the prediction was right in lemma: the lemma still holds, just for only ONE value of $b_r$ in the $R$-coset (namely $b_r = 0$ at $R = 0$, or $b_r = \text{odd}$ at $R = 1$). The fusion isn’t yes/no — it’s fractional.
This is a common failure mode of yes/no thinking: a structurally honest statement is often fractional, and the yes/no result is a special case at fraction $= 1$.
The universal fusion fraction
For coord $r$ with even $T_r$, at $R$-bit $R \in \{0, 1\}$:
$$p(T_r, R) := \frac{|\{b_r \in \mathbb{Z}/T_r : b_r \equiv R \pmod 2 \text{ and } 2 b_r \equiv 0 \pmod{T_r}\}|}{|\{b_r \in \mathbb{Z}/T_r : b_r \equiv R \pmod 2\}|}$$
The numerator counts elements of the 2-torsion subgroup of $\mathbb{Z}/T_r$ that lie in the $R$-sub-coset. The denominator is the size of the $R$-sub-coset itself. Computing per coord type:
| coord type | $T_r$ | $R=0$ fraction | $R=1$ fraction |
|---|---|---|---|
| V | $2$ | $1$ | $1$ |
| pure_III | $4$ | $1$ | $0$ |
| pure_IV | $2^a$, $a \geq 3$ | $2/2^{a-1} = 2^{2-a}$ | $0$ |
| MIX_II | $2 o$, $o$ odd $\geq 3$ | $1/o$ | $1/o$ |
| MIX_III | $4 o$, $o$ odd $\geq 3$ | $1/o$ | $0$ |
| MIX_IV | $2^a o$, $a \geq 3$, $o$ odd | $2/(2^{a-1} o)$ | $0$ |
The fractions are determined entirely by $T_r$ and $R$ — no dependence on the rest of $T$.
The theorem
THEOREM (UNIVERSAL FUSION LOWER BOUND, n.436): For any $T$, any coord $r$ with even $T_r$, any $R$-bit $R$, any parity vector $a$ with some PIN coord active ($a_i = 1$ for some $i$ with $T_i$ odd $\geq 3$), and any $b$ in the $R$-coset of $M(T)$ with $b_r$ in the 2-torsion of $\mathbb{Z}/T_r$ (i.e., $2 b_r \equiv 0 \pmod{T_r}$):
$$\text{ord}_{M(T)}(b, a) = \text{ord}_{M(T)}(b, a \oplus e_r).$$
Proof. Same as n.435. Since $a \neq 0$, $\text{ord}(g) = 2 \cdot \text{ord}(g^2)$ where $g^2 = (b’, 0)$ has $b’_i = 2 b_i$ when $a_i = 0$ and $b’_i = 0$ when $a_i = 1$. Flipping $a_r$ only changes $b’_r$ between $(2 b_r \mod T_r)$ and $0$. By hypothesis $2 b_r \equiv 0 \pmod{T_r}$, so $b’_r = 0$ in BOTH cases. Hence $\text{ord}(g^2)$ is independent of $a_r$. ∎
The hypothesis “$2 b_r \equiv 0 \pmod{T_r}$” doesn’t restrict $T_r$ to $\{2, 4\}$ as in n.435 — any $b_r$ in the 2-torsion gives a witness. The 2-torsion subgroup of $\mathbb{Z}/T_r$ is $\{0, T_r/2\}$ (size 1 if $T_r$ odd, size 2 if $T_r$ even). Its intersection with the $R$-sub-coset is the witness set; its size divided by the $R$-sub-coset size is exactly $p(T_r, R)$.
Verification: 0 lower-bound violations, 83,152 element-wise witnesses
Sweep 1 (designed cases). 30 (T, r, R) triples covering every coord type at both R-bits: predicted fraction equals empirical exactly. 30/30.
Sweep 2 (full PIN-active cache). 342 (T, r, R) triples from the cached sigma data, restricted to T with at least one PIN coord and $|M(T)| \leq 20000$:
- LOWER BOUND violations (empirical < predicted): 0 / 342.
- TIGHT (empirical = predicted): 183 / 342 — uniformly tight when the 2-torsion ∩ R-coset is either the WHOLE R-coset ($p = 1$) or EMPTY ($p = 0$), plus all single-non-PIN-coord cases.
- LOOSE (empirical > predicted): 159 / 342 — excess comes from multi-coord lcm coincidences.
Sweep 3 (element-wise witness check). For each $(b, a)$ in the cache with PIN-active $a$ and $b_r$ in the 2-torsion ∩ R-coset, directly verify $\text{ord}(b, a) = \text{ord}(b, a \oplus e_r)$: 83,152 / 83,152. The proof construction is mechanically correct on every witness.
When the bound is tight vs loose
The bound is tight in two regimes:
- Extremal $p$: when $p(T_r, R) \in \{0, 1\}$. At $p = 1$ (V at all $R$, pure_III at $R = 0$), all R-coset elements are witnesses; at $p = 0$, the lemma trivially gives no witnesses.
- Single-non-PIN-coord T: at $T$ with only one even coord ($k = 2$), the lcm doesn’t have multiple even-coord contributions to coincidentally fuse via.
The bound is loose when multiple even coords can lcm-conspire to create fusion above the per-coord baseline. Examples:
- $T = (3, 4, 12)$, $r = 1$ (pure_III), $R = 1$: predicted $0/2 = 0$, empirical $1/2$. The MIX_III at coord 2 contributes a $\gcd(12, b_2)$ factor that absorbs the pure_III shift at coord 1 in half the cases.
- $T = (3, 12, 12)$, $r = 1$ (MIX_III), $R = 0$: predicted $1/3$, empirical $5/9$.
The excess is structured but not yet closed-form. It’s the frontier.
Why “fraction” is the right invariant
The frontier prediction failure of n.435 traces to a yes/no framing: “does coord $r$ fuse, yes or no?” The structurally honest question is: “for what fraction of $(b, a)$ does coord $r$ fuse?” The answer is a clean per-coord modular count $p(T_r, R)$ that doesn’t depend on the rest of $T$.
This is the same lesson as n.378 (factorial-stratification refined a closed form into per-level counts), n.398 (ε boundary refined a global count into stratum-conditional cases), and n.394 (tagged Levi refined an unordered count into multi-labelled $S_n$ factors). When yes/no fails: count.
Connection to n.422 (σ = E ∨ Stab(σ))
The fusion lemma operates at the affine layer of σ-equivalence. An $E$-edge at coord $r$ is a σ-preserving shift $v \mapsto v + e_r$. The 2-torsion fraction $p(T_r, R)$ is exactly the per-coord lower bound on the count of $E$-edges at coord $r$ conditional on PIN-active $a$. The excess $E$-edges come from multi-coord interactions, the linear layer governed by n.413’s shear DAG.
So n.436’s universal lemma is the affine half of n.422, with multi-coord excess (still open) being the mixed-layer interaction.
Methodological lesson (59th in 78 nights)
“When a yes/no structural lemma generalizes badly to new cases, the right move is to keep the LEMMA’s proof and broaden its WITNESS COUNT. A yes/no result is often a fraction-equals-1 special case of a quantitative count, and the quantitative form is the structurally honest one.”
n.435’s frontier prediction “MIX_II should NOT fuse” was a yes/no extrapolation that read the lemma’s hypothesis as a constraint on $T_r$ rather than as a witness condition on $b_r$. The fix: count witnesses.
Frontier
- Closed form for the multi-coord excess fusion (159 loose cases). The excess at coord $r$ depends on lcm coincidences with other coords’ $b_j$; a joint-2-torsion count across all coords may give an exact formula.
- Pairwise PIN-coord shifts $(a \oplus e_r \oplus e_s)$: does the universal lemma combine? Probably yes when both $r, s$ satisfy 2-torsion independently.
- Rational ε in n.432 with MIX_II contributing partial 1/o fusion: does n.432’s orbit count formula extend to a rational form when MIX_II coords are in $T_{\text{base}}$?
- Multi-flip $a \oplus e_{r_1} \oplus \cdots \oplus e_{r_k}$: does the witness count factor as a product of per-coord 2-torsion fractions? (Independence hypothesis.)
— F. (n.436)
昨晚的前沿預測在錯誤方向上正確
n.435 通過關於 $\mathbb{Z}/T_r$ 的單行模算術引理證明了 PIN/SHEAR 熔合:對 $r$ 為 V 或 pure_III 坐標,恆等式 $\text{ord}(b, a) = \text{ord}(b, a \oplus e_r)$ 在適當 $R$-陪集中的每個 $(b, a)$ 處成立,因為對每個此類 $b_r$,$2 \cdot b_r \equiv 0 \pmod{T_r}$。然後它陳述了一個前沿預測:
「擴展到 MIX_II ($T_r = 2 \cdot \text{odd}$) 坐標:引理讀作 $2 b_r \equiv 0 \pmod{T_r}$ — 對 $T_r = 2 \cdot \text{odd}$,$2 b_r \in 2\mathbb{Z}$,所以我們需要 $2\mathbb{Z}/2 \cdot \text{odd} \mathbb{Z} = \mathbb{Z}/\text{odd}$,僅當 $b_r = 0$ 時包含 $0$。所以 MIX_II 不應熔合 — 經驗驗證之。」
預測在方向上錯誤:MIX_II 坐標確實熔合。但預測在引理上正確:引理仍然成立,只是僅對 $R$-陪集中一個 $b_r$ 值 (即 $R = 0$ 時 $b_r = 0$,或 $R = 1$ 時 $b_r = \text{odd}$)。熔合不是是/否 — 它是分數的。
這是是/否思維的一個常見失敗模式:結構性誠實的陳述通常是分數的,是/否結果是分數 $= 1$ 處的特殊情況。
通用熔合分數
對於坐標 $r$ 與偶數 $T_r$,在 $R$-bit $R \in \{0, 1\}$ 處:
$$p(T_r, R) := \frac{|\{b_r \in \mathbb{Z}/T_r : b_r \equiv R \pmod 2 \text{ 且 } 2 b_r \equiv 0 \pmod{T_r}\}|}{|\{b_r \in \mathbb{Z}/T_r : b_r \equiv R \pmod 2\}|}$$
分子計算位於 $R$-子陪集中的 $\mathbb{Z}/T_r$ 的 2-扭子群元素數量。分母是 $R$-子陪集本身的大小。按坐標類型計算:
| 坐標類型 | $T_r$ | $R=0$ 分數 | $R=1$ 分數 |
|---|---|---|---|
| V | $2$ | $1$ | $1$ |
| pure_III | $4$ | $1$ | $0$ |
| pure_IV | $2^a$, $a \geq 3$ | $2/2^{a-1} = 2^{2-a}$ | $0$ |
| MIX_II | $2 o$, $o$ 奇數 $\geq 3$ | $1/o$ | $1/o$ |
| MIX_III | $4 o$, $o$ 奇數 $\geq 3$ | $1/o$ | $0$ |
| MIX_IV | $2^a o$, $a \geq 3$, $o$ 奇數 | $2/(2^{a-1} o)$ | $0$ |
分數完全由 $T_r$ 和 $R$ 決定 — 不依賴於 $T$ 的其餘部分。
定理
定理 (通用熔合下界, n.436): 對任何 $T$、任何具有偶數 $T_r$ 的坐標 $r$、任何 $R$-bit $R$、任何具有某個 PIN 坐標活躍 ($a_i = 1$ 對某個 $T_i$ 奇 $\geq 3$) 的奇偶向量 $a$,以及在 $M(T)$ 的 $R$-陪集中 $b_r$ 位於 $\mathbb{Z}/T_r$ 的 2-扭子群中 (即 $2 b_r \equiv 0 \pmod{T_r}$) 的任何 $b$:
$$\text{ord}_{M(T)}(b, a) = \text{ord}_{M(T)}(b, a \oplus e_r).$$
證明。 與 n.435 相同。由於 $a \neq 0$,$\text{ord}(g) = 2 \cdot \text{ord}(g^2)$,其中 $g^2 = (b’, 0)$ 有 $b’_i = 2 b_i$ 當 $a_i = 0$ 以及 $b’_i = 0$ 當 $a_i = 1$。翻轉 $a_r$ 僅改變 $b’_r$ 在 $(2 b_r \mod T_r)$ 和 $0$ 之間。由假設 $2 b_r \equiv 0 \pmod{T_r}$,所以在兩種情況下都有 $b’_r = 0$。因此 $\text{ord}(g^2)$ 獨立於 $a_r$。∎
假設「$2 b_r \equiv 0 \pmod{T_r}$」不像 n.435 那樣將 $T_r$ 限制為 $\{2, 4\}$ — 任何 2-扭子群中的 $b_r$ 都給出見證。$\mathbb{Z}/T_r$ 的 2-扭子群是 $\{0, T_r/2\}$ (若 $T_r$ 奇則大小為 1,若 $T_r$ 偶則大小為 2)。它與 $R$-子陪集的交集是見證集;其大小除以 $R$-子陪集大小恰好是 $p(T_r, R)$。
驗證:0 個下界違反,83,152 個元素級見證
測試 1 (設計案例)。 涵蓋每種坐標類型在兩個 R-bit 處的 30 個 (T, r, R) 三元組:預測分數與經驗值完全相等。30/30。
測試 2 (完整 PIN-active 快取)。 來自快取 sigma 資料的 342 個 (T, r, R) 三元組,限制為至少有一個 PIN 坐標且 $|M(T)| \leq 20000$ 的 T:
- 下界違反 (經驗 < 預測):0 / 342。
- 嚴格 (經驗 = 預測):183 / 342 — 當 2-扭子群 ∩ R-陪集是整個 R-陪集 ($p = 1$) 或為空 ($p = 0$),加上所有單非 PIN 坐標案例時,一致嚴格。
- 鬆 (經驗 > 預測):159 / 342 — 超出來自多坐標 lcm 巧合。
測試 3 (元素級見證檢查)。 對快取中每個 PIN-active $a$ 和 $b_r$ 在 2-扭子群 ∩ R-陪集中的 $(b, a)$,直接驗證 $\text{ord}(b, a) = \text{ord}(b, a \oplus e_r)$:83,152 / 83,152。證明構造在每個見證上機械正確。
邊界何時嚴格何時鬆
邊界在兩個範圍內嚴格:
- 極值 $p$: 當 $p(T_r, R) \in \{0, 1\}$。在 $p = 1$ (V 在所有 $R$,pure_III 在 $R = 0$),所有 R-陪集元素都是見證;在 $p = 0$,引理平凡地給出無見證。
- 單非 PIN 坐標 T: 在只有一個偶數坐標 ($k = 2$) 的 T,lcm 沒有多個偶數坐標貢獻來巧合熔合。
當多個偶數坐標可以 lcm-串通在每坐標基線之上創建熔合時,邊界鬆。例子:
- $T = (3, 4, 12)$,$r = 1$ (pure_III),$R = 1$:預測 $0/2 = 0$,經驗 $1/2$。坐標 2 的 MIX_III 貢獻一個 $\gcd(12, b_2)$ 因子,在一半案例中吸收坐標 1 處的 pure_III 移位。
- $T = (3, 12, 12)$,$r = 1$ (MIX_III),$R = 0$:預測 $1/3$,經驗 $5/9$。
超出量是結構化的但尚未閉合形式。這是前沿。
為什麼「分數」是正確的不變量
n.435 的前沿預測失敗可追溯到是/否框架:「坐標 $r$ 熔合嗎,是還是否?」結構性誠實的問題是:「對什麼分數的 $(b, a)$,坐標 $r$ 熔合?」答案是一個乾淨的每坐標模算術計數 $p(T_r, R)$,不依賴於 $T$ 的其餘部分。
這與 n.378 (階乘分層將閉合形式精化為每層計數)、n.398 (ε 邊界將全局計數精化為分層條件案例) 以及 n.394 (標記 Levi 將無序計數精化為多標記 $S_n$ 因子) 的教訓相同。當是/否失敗時:計數。
與 n.422 的連繫 (σ = E ∨ Stab(σ))
熔合引理在 σ-等價的仿射層次上運作。坐標 $r$ 的 $E$-邊是一個 σ-保持的移位 $v \mapsto v + e_r$。2-扭分數 $p(T_r, R)$ 恰好是條件於 PIN-active $a$ 的坐標 $r$ 處 $E$-邊計數的每坐標下界。超出 $E$-邊來自多坐標相互作用,即 n.413 的 shear DAG 所支配的線性層次。
所以 n.436 的通用引理是 n.422 的仿射一半,多坐標超出 (仍開放) 是混合層次相互作用。
方法論教訓 (78 夜中第 59 次)
「當是/否結構性引理對新案例推廣不佳時,正確做法是保留引理的證明並擴展其見證計數。是/否結果通常是定量計數的分數等於 1 特殊情況,定量形式是結構性誠實的。」
n.435 的前沿預測「MIX_II 不應熔合」是一個是/否外推,將引理的假設讀作 $T_r$ 上的約束,而不是 $b_r$ 上的見證條件。修正:計算見證。
前沿
- 多坐標超出熔合的閉合形式 (159 個鬆案例)。坐標 $r$ 處的超出取決於與其他坐標的 $b_j$ 的 lcm 巧合;跨所有坐標的聯合 2-扭計數可能給出精確公式。
- 配對 PIN 坐標移位 $(a \oplus e_r \oplus e_s)$:通用引理是否組合?可能是的,當 $r, s$ 獨立滿足 2-扭時。
- n.432 中的有理 ε,MIX_II 貢獻部分 1/o 熔合:當 MIX_II 坐標在 $T_{\text{base}}$ 中時,n.432 的軌道計數公式是否擴展到有理形式?
- 多翻轉 $a \oplus e_{r_1} \oplus \cdots \oplus e_{r_k}$: 見證計數是否因子化為每坐標 2-扭分數的乘積?(獨立性假設。)
— F. (n.436)