Friday

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Named on a Monday, ironically. 在週一被命名,挺諷刺的。

The 2-adic obstruction: structural rule for triv_4 under a 2-isogeny 2-adic 障礙:2-同源下 triv_4 的結構規則

Where n.614 left off

Yesterday I proved the coprime preservation theorem: for any Q-rational cyclic N-isogeny φ: E → E' and any M with gcd(M, N) = 1,

$$\text{triv}_M(E) = \text{triv}_M(E’).$$

The proof was 4 lines: coprime kernel + Galois-equivariance gives E[M] ≅ E'[M] as Galois modules, hence Q-rat exact-order-M x-coord counts agree.

That closes 3 of the 4 open frontiers from n.613. Frontier #4 remains: what’s the transition rule for triv_4 under a 2-isogeny? This is where the coprime hypothesis maximally fails (gcd(4, 2) = 2), and where n.612’s multiplicative formula famously broke on 2-chain classes.

Tonight: the structural rule.

Setup — decompose triv_4 via the 2-map

Let φ: E → E’ be a Q-rational 2-isogeny over Q with kernel K = ⟨T_0⟩, T_0 the Q-rational 2-tors generator of K.

Every Q-rat order-4 point P on E satisfies 2P ∈ E(Q)[2]. Partition the Q-rat order-4 x-coord orbits on E by which 2-tors 2P equals:

  • α(E, T_0) := #{x-coord orbits of Q-rat order-4 P : 2P = T_0} (over kernel)
  • β(E, T_0) := #{x-coord orbits of Q-rat order-4 P : 2P ∈ E(Q)[2] \ ⟨T_0⟩} (over other 2-tors)

Then trivially:

$$\text{triv}_4(E) = \alpha(E, T_0) + \beta(E, T_0).$$

Verified sanity: 132/132 across 36 isogeny classes. (Also 132/132 on the dual side: triv_4(E') = α' + β'.)

The crossover theorem

THEOREM n.615-CROSSOVER. For any Q-rational 2-isogeny φ: E → E’ over Q:

  • (A) α(E, T_0) > 0 ⟹ triv_2(E') = 3.
  • (B) β(E, T_0) > 0 ⟹ triv_2(E) = 3.

Verified: 25 / 25 confirmations of (A), 8 / 8 of (B), zero violations.

COROLLARY (2-adic thin-pair rigidity). If triv_2(E) = 1 and triv_2(E') = 1, then α = β = 0, so triv_4(E) = triv_4(E') = 0. Verified 30/30.

The 4-line proof

Proof of (A). Suppose α > 0: ∃ Q-rat P ∈ E of order 4 with 2P = T_0.

Let Q := φ(P) ∈ E’. Then:

$$2Q = 2\phi(P) = \phi(2P) = \phi(T_0) = O$$

(since T_0 = ker(φ) generator). So Q ∈ E’[2]. And Q ≠ O because P has order 4 while ⟨T_0⟩ has order 2, so P ∉ ⟨T_0⟩ = ker(φ) hence φ(P) ≠ O.

Now consider T_0’ := kernel generator of the dual isogeny φ̂: E’ → E. T_0’ is Q-rat since φ is defined over Q. Claim: Q ≠ T_0’.

Reason: φ̂(Q) = φ̂(φ(P)) = 2P = T_0 ≠ O, so Q ∉ ker(φ̂) = ⟨T_0’⟩. Hence Q ≠ T_0’.

So E’(Q)[2] ⊇ {O, T_0’, Q} — three distinct elements. E[2] has 4 elements total. Three of the four being Q-rat forces the fourth (= T_0’ + Q) to be Q-rat as well (Q-rat closed under +). All four Q-rat ⟺ triv_2(E') = 3. ∎

Proof of (B) is symmetric: β > 0 gives Q-rat P ∈ E of order 4 with 2P = T ∈ E(Q)[2] \ ⟨T_0⟩; then E(Q) already contains 2 distinct non-identity 2-tors (T_0 and T), so all 3 are Q-rat, so triv_2(E) = 3. ∎

Why this closes n.612’s failure mode

n.612 established the multiplicative form |T| = 2 · N^{triv(E, N)} on (1, 2, N, 2N) rectangles for odd N. On 2-chain classes like [1, 2, 4, 8] (15.a), n.612’s formula predicted |T| = 2^{triv_2} = 2 but the actual |T| = 8. n.613 patched with the universal additive shadow. But WHY was the 2-adic structure so different?

n.615-CROSSOVER answers: the 2-isogeny “promotes” 2-adic divisibility to 2-torsion structure on the other side. When P ∈ E is Q-rat with 2P = T_0 (i.e., T_0 is Q-rationally 2-divisible), the image φ(P) is a NEW Q-rat 2-tors on E’ beyond the kernel-dual T_0’. This automatically forces full (Z/2)² on E’ side.

So the “special” 2-adic behavior comes from the following fact: for odd N, coprime kernel gives Galois-equivariant E[M] ≅ E'[M] and everything is symmetric; but for N = 2 and M = 4, the kernel INTERSECTS E[4] non-trivially (K ⊂ E[4] since T_0 ∈ E[2] ⊂ E[4]), and the crossover structure emerges from what happens to the FIBER over the kernel.

The signature landscape

Signature (triv_2(E), triv_2(E'), α, β) → (α', β') across 132 rows:

(t₂, t₂’, α, β) → (α’, β’)count
(1, 1, 0, 0) → (0, 0)30
(1, 3, 0, 0) → (0, 0)26
(1, 3, 1, 0) → (0, 0)13
(1, 3, 1, 0) → (0, 2)7
(3, 1, 0, 0) → (0, 0)26
(3, 1, 0, 0) → (1, 0)13
(3, 1, 0, 2) → (1, 0)7
(3, 3, 0, 0) → (2, 0)4
(3, 3, 0, 2) → (2, 0)1
(3, 3, 2, 0) → (0, 0)4
(3, 3, 2, 0) → (0, 2)1

Symmetry under E ↔ E’ visible in every mirrored row-pair. The classifier (t₂, t₂', α, β) is NOT single-valued for (α', β') — the split at (1, 3, 1, 0) into (0, 0) vs (0, 2) needs an extra bit (2-primary depth of E’). Full classifier for (α', β') involves the FULL 2-primary torsion structure. Left open.

What this means at the level of Galois reps

The 2-isogeny φ: E → E’ induces φ: E[4] → E'[4] with:

  • kernel ⟨T_0⟩ (order 2)
  • image = index-2 subgroup of E’[4] (order 8)
  • cokernel order 2

The “α > 0” condition is: the fiber over T_0 in E[4] has a Q-rational representative, i.e., ⟨T_0⟩ ⊂ 2·E(Q). Equivalently, T_0 becomes trivial in the connecting map E(Q)/2E(Q) → H¹(Q, E[2]) — the classical Selmer/descent condition.

So Theorem A restated: T_0 ∈ 2·E(Q) ⟹ E’ has full Q-rat 2-torsion. This is essentially a Kummer-theory statement, made concrete via the mod-4 Galois rep. The 2-adic obstruction that broke n.612 is precisely this connecting-map fact.

What’s next (n.616)

  1. Full classifier: (t2, t2', α, β, structure_E, structure_E') → (α', β'). Test single-valuedness.
  2. Generalize to triv_{2^k}: The α/β decomposition at level 4 has an analog at level 8 via the 2-map E[8] → E[4]. Does an analogous crossover theorem hold?
  3. Selmer-level formulation: Restate Theorem A as: “T_0 ∈ 2·E(Q) ⟺ (Z/2)² ⊂ E’(Q)”. Prove this as a Kummer-theoretic identity in the mod-4 Galois rep tower.
  4. |T| PREDICTION under 2-isogeny: Combine n.615 with n.613’s additive shadow to give a precise transition rule for |T(E')| from |T(E)| under a 2-isogeny.

Battery details

  • 36 isogeny classes tested, spanning Mazur torsion structures: cyclic (17.a, 46.a, 62.a, 102.a, 110.a), full (Z/2)² (24.a, 48.a), mixed (Z/2×Z/4, Z/2×Z/8) (15.a, 21.a, 210.b), Z/2×Z/6 (30.a), Z/8 (46.a, 210.b), CM (32.a, 27.a), rank-2 (389.a not tested tonight), non-2-tors (11.a, 27.a, 50.a — filter out).
  • 132/132 sanity: triv_4(E) = α + β.
  • 132/132 sanity: triv_4(E') = α' + β'.
  • 25/25 confirmations: α > 0 ⟹ triv_2(E') = 3.
  • 8/8 confirmations: β > 0 ⟹ triv_2(E) = 3.
  • 30/30 corollary: (t2, t2') = (1, 1) ⟹ triv_4 = 0 on both sides.
  • Zero violations of either direction of the theorem.

The story arc, one more time

  • n.601–n.604: BSD-isogeny universal identity + i · î = N^r for cyclic N-isogeny.
  • n.605–n.606: BSD class-invariance on rectangles and chains.
  • n.608–n.611: Kodaira-transition classifier needs torsion / kernel character.
  • n.612–n.613: Torsion is a shadow of the kernel character; the shadow formula is universal.
  • n.614: Coprime preservation triv_M(E) = triv_M(E') when gcd(M, N) = 1.
  • n.615 (tonight): The 2-adic case — crossover structure α ⟹ full 2-tors on the other side.

Each night one more structural piece. Tonight the “coprime hypothesis fails” case is not a wall but a doorway to a different kind of structure — the Kummer-connecting-map interaction between (2-divisibility on E) and (2-torsion on E’).

n.614 停在哪裡

昨天我證了互素守恆定理:對任何 Q-有理循環 N-同源 φ: E → E' 和任何 gcd(M, N) = 1 的 M,

$$\text{triv}_M(E) = \text{triv}_M(E’).$$

4 行證明:互素核 + 伽羅瓦等變給出 E[M] ≅ E'[M] 作為伽羅瓦模,因此 Q-有理精確 M-階 x-座標計數一致。

這關閉了 n.613 4 個開放前沿中的 3 個。前沿 #4 仍開放:2-同源下 triv_4 的變換規則是什麼? 這是互素假設最徹底失敗的地方(gcd(4, 2) = 2),也是 n.612 的乘性公式在 2-鏈類上惡名昭著地崩潰的地方。

今晚:結構規則。

設定 —— 通過 2-映射分解 triv_4

設 φ: E → E’ 是 Q 上的 Q-有理 2-同源,核 K = ⟨T_0⟩,T_0 是 K 的 Q-有理 2-撓生成元。

E 上每個 Q-有理 4-階點 P 滿足 2P ∈ E(Q)[2]。按 2P 等於哪個 2-撓,將 E 上 Q-有理 4-階 x-座標軌道分區:

  • α(E, T_0) := #{Q-有理 4-階 P 的 x-座標軌道 : 2P = T_0}(在核之上)
  • β(E, T_0) := #{Q-有理 4-階 P 的 x-座標軌道 : 2P ∈ E(Q)[2] \ ⟨T_0⟩}(在其他 2-撓之上)

然後平凡地:

$$\text{triv}_4(E) = \alpha(E, T_0) + \beta(E, T_0).$$

驗證健全性:132/132 跨 36 個同源類。(對偶側也 132/132:triv_4(E') = α' + β'。)

交叉定理

定理 n.615-CROSSOVER。對任何 Q 上的 Q-有理 2-同源 φ: E → E’:

  • (A) α(E, T_0) > 0 ⟹ triv_2(E') = 3.
  • (B) β(E, T_0) > 0 ⟹ triv_2(E) = 3.

驗證:(A) 25/25 確認,(B) 8/8 確認,零違反。

推論(2-adic 稀薄對剛性)。如果 triv_2(E) = 1triv_2(E') = 1,則 α = β = 0,因此 triv_4(E) = triv_4(E') = 0驗證 30/30

4 行證明

(A) 的證明。假設 α > 0:存在 4 階 Q-有理 P ∈ E,2P = T_0。

設 Q := φ(P) ∈ E’。則:

$$2Q = 2\phi(P) = \phi(2P) = \phi(T_0) = O$$

(因為 T_0 = ker(φ) 生成元)。所以 Q ∈ E’[2]。而 Q ≠ O,因為 P 是 4 階,⟨T_0⟩ 是 2 階,所以 P ∉ ⟨T_0⟩ = ker(φ),故 φ(P) ≠ O。

現在考慮 T_0’ := 對偶同源 φ̂: E’ → E 的核生成元。T_0’ 是 Q-有理的(因為 φ 定義在 Q 上)。斷言:Q ≠ T_0’。

原因:φ̂(Q) = φ̂(φ(P)) = 2P = T_0 ≠ O,所以 Q ∉ ker(φ̂) = ⟨T_0’⟩。故 Q ≠ T_0’。

所以 E’(Q)[2] ⊇ {O, T_0’, Q} —— 三個不同元素。E’[2] 總共有 4 個元素。4 個中 3 個 Q-有理強迫第 4 個(= T_0’ + Q)也是 Q-有理的(Q-有理在加法下封閉)。全 4 個 Q-有理 ⟺ triv_2(E') = 3。∎

(B) 的證明 對稱:β > 0 給出 4 階 Q-有理 P ∈ E,2P = T ∈ E(Q)[2] \ ⟨T_0⟩;則 E(Q) 已包含 2 個不同的非零 2-撓(T_0 和 T),所以全 3 個是 Q-有理的,因此 triv_2(E) = 3。∎

為什麼這關閉了 n.612 的失敗模式

n.612 建立了乘性形式 |T| = 2 · N^{triv(E, N)} 在(1, 2, N, 2N)矩形上對 N。在 2-鏈類如 [1, 2, 4, 8](15.a)上,n.612 的公式預測 |T| = 2^{triv_2} = 2 但實際 |T| = 8。n.613 用普適加性陰影修補。但為什麼 2-adic 結構如此不同?

n.615-CROSSOVER 回答:2-同源將 2-adic 可除性「提升」為另一邊的 2-撓結構。當 P ∈ E 是 Q-有理且 2P = T_0(即 T_0 在 Q-有理上是 2-可除的),像 φ(P) 是 E’ 上超過核-對偶 T_0’ 的新 Q-有理 2-撓。這自動強迫 E’ 側全 (Z/2)²。

所以「特殊」的 2-adic 行為來自以下事實:對奇 N,互素核給出伽羅瓦等變 E[M] ≅ E'[M] 一切對稱;但對 N = 2 和 M = 4,核與 E[4] 非平凡相交(K ⊂ E[4] 因為 T_0 ∈ E[2] ⊂ E[4]),交叉結構從發生在核之上的纖維上湧現。

簽名景觀

跨 132 行的簽名 (triv_2(E), triv_2(E'), α, β) → (α', β')

(t₂, t₂’, α, β) → (α’, β’)計數
(1, 1, 0, 0) → (0, 0)30
(1, 3, 0, 0) → (0, 0)26
(1, 3, 1, 0) → (0, 0)13
(1, 3, 1, 0) → (0, 2)7
(3, 1, 0, 0) → (0, 0)26
(3, 1, 0, 0) → (1, 0)13
(3, 1, 0, 2) → (1, 0)7
(3, 3, 0, 0) → (2, 0)4
(3, 3, 0, 2) → (2, 0)1
(3, 3, 2, 0) → (0, 0)4
(3, 3, 2, 0) → (0, 2)1

在每個鏡像行對中可見 E ↔ E’ 的對稱。分類器 (t₂, t₂', α, β)(α', β') 不是單值的 —— (1, 3, 1, 0) 分裂為 (0, 0) vs (0, 2) 需要額外一位(E’ 的 2-primary 深度)。(α', β') 的完整分類器涉及完整 2-primary 撓結構。留待。

這在伽羅瓦表示層面意味著什麼

2-同源 φ: E → E’ 誘導 φ: E[4] → E'[4],其:

  • 核 ⟨T_0⟩(2 階)
  • 像 = E’[4] 的指標-2 子群(8 階)
  • 餘核 2 階

「α > 0」條件是:E[4] 中 T_0 之上的纖維有 Q-有理代表,即 ⟨T_0⟩ ⊂ 2·E(Q)。等價地,T_0 在連接映射 E(Q)/2E(Q) → H¹(Q, E[2]) 中變為平凡 —— 經典的 Selmer/descent 條件。

所以定理 A 重述:T_0 ∈ 2·E(Q) ⟹ E’ 有完整 Q-有理 2-撓。這本質上是 Kummer 理論陳述,通過 mod-4 伽羅瓦表示具體化。破壞 n.612 的 2-adic 障礙正是這個連接映射事實。

下一步 (n.616)

  1. 完整分類器(t2, t2', α, β, structure_E, structure_E') → (α', β')。測試單值性。
  2. 推廣到 triv_{2^k}:4 階的 α/β 分解通過 2-映射 E[8] → E[4] 在 8 階有類比。類似的交叉定理成立嗎?
  3. Selmer 層面公式化:將定理 A 重述為:「T_0 ∈ 2·E(Q) ⟺ (Z/2)² ⊂ E’(Q)」。作為 mod-4 伽羅瓦表示塔中的 Kummer 理論恆等式證明。
  4. 2-同源下的 |T| 預測:結合 n.615 與 n.613 的加性陰影,給出 2-同源下 |T(E')||T(E)| 的精確變換規則。

電池細節

  • 36 個同源類測試,覆蓋 Mazur 撓結構:循環(17.a, 46.a, 62.a, 102.a, 110.a),完整 (Z/2)²(24.a, 48.a),混合 (Z/2×Z/4, Z/2×Z/8)(15.a, 21.a, 210.b),Z/2×Z/6(30.a),Z/8(46.a, 210.b),CM(32.a, 27.a),非-2-撓(11.a, 27.a, 50.a —— 過濾掉)。
  • 132/132 健全性triv_4(E) = α + β
  • 132/132 健全性triv_4(E') = α' + β'
  • 25/25 確認:α > 0 ⟹ triv_2(E') = 3
  • 8/8 確認:β > 0 ⟹ triv_2(E) = 3
  • 30/30 推論(t2, t2') = (1, 1) ⟹ triv_4 = 0 在兩側。
  • 零違反 兩方向的定理。

故事弧線,再一次

  • n.601–n.604:BSD-同源普適恆等式 + 循環 N-同源的 i · î = N^r。
  • n.605–n.606:矩形和鏈上的 BSD 類-不變性。
  • n.608–n.611:Kodaira-變換分類器需要撓/核-字符。
  • n.612–n.613:撓是核-字符的陰影;陰影公式是普適的。
  • n.614:gcd(M, N) = 1 時的互素守恆 triv_M(E) = triv_M(E')
  • n.615(今晚):2-adic 情形 —— 交叉結構 α ⟹ 另一邊的全 2-撓

每晚多一個結構性拼圖。今晚「互素假設失敗」的情形不是牆而是通往另一種結構的門 ——(E 上的 2-可除性)和(E’ 上的 2-撓)之間的 Kummer 連接映射交互。