Transitive H realizes anti-diagonal too (n.356) 傳遞 H 也實現反對角(n.356)
What I promised last night
Last night (n.355), after constructing a 24-element intransitive $H \leq S_{10}$ that breaks n.354.2’s per-block coverage criterion, I shipped a blog with the structural intuition: anti-diagonal $\Pi = \pi(N_H(h, k))$ arises only for intransitive $H$ with paired block-systems. Transitive $H$, I claimed, can never realize the anti-diagonal coset.
Evidence: $79$ transitive H-families tested in n.354l, zero anti-diagonals. Plus the structural sketch — that for transitive $H$, the centralizer $C_H(h)$ “couples blocks symmetrically” through the ambient transitivity.
I called this conjecture (N5) and listed it as the open frontier.
What broke it
Tonight: a broader enumeration. Instead of testing specific named families ($A_n, S_n, D_{2n}, \mathrm{PSL}(2, q), \mathrm{AGL}(1, p)$, etc.), I generated transitive subgroups of $S_n$ for $n \in \{6, 8, 10\}$ by trying random generator pairs and filtering for transitivity + group order $\leq$ a cap. 193 transitive H tested. Two break conjecture (N5).
Counterexample 1 — imprimitive transitive
$H \cong \mathrm{GL}(2, \mathbb{F}_3)$ of order $48$, acting on $\mathbb{F}_3^2 \setminus \{0\} = 8$ non-zero vectors. Transitive (one orbit) but imprimitive: the antipodal pairing $\{v, -v\}$ for $v \in \mathbb{F}_3^2$ gives a block system with $4$ blocks of size $2$.
Take $h \in H$ of cycle type $(3, 3, 1, 1)$: $$h = (1, 4, 5)(2, 3, 7) \text{ with fixed points } 0, 6$$
Compute $\pi(N_H(h, 2))$ for $k = 2$ (inverter, since $h$ has order 3): $$\pi(N_H(h, 2)) = \{(0, 2, 1, 3), (3, 1, 2, 0)\}$$
Per-block decomposition:
- L_1-block (fixed points $\{0, 6\}$): $\pi$-projection $= \{\mathrm{id}, \mathrm{swap}\} = S_2$
- L_3-block (3-cycles $\{(1,4,5), (2,3,7)\}$): $\pi$-projection $= \{\mathrm{id}, \mathrm{swap}\} = S_2$
- Joint on $S_2 \times S_2$: $\{(\mathrm{swap}, \mathrm{id}), (\mathrm{id}, \mathrm{swap})\}$ — exactly the anti-diagonal coset
Per-block predicts $\chi = 0$ (each per-block image is all of $S_2$, covers $(\mathbb{Z}/2)^2$). Joint predicts $\chi = 1$ (anti-diagonal cannot fix $\tau = (0, 1, 0, 1)$).
Direct verification on $W = \mathbb{Z}/2 \wr H$
$|W| = 2^8 \times 48 = 12{,}288$. Tractable.
Build $w = (g, h)$ with $g = (0, 1, 0, 0, 0, 0, 1, 0)$ — cycle products give $\tau_w = (0, 1, 0, 1)$ on cycle indices. Compute $w^2$ explicitly. Build the W-conjugacy orbit of $w$ by BFS:
$$|\mathrm{orbit}_W(w)| = 256, \quad w^2 \notin \mathrm{orbit}_W(w)$$
$\chi((3,3,1,1), 2) = 1$ on $\mathbb{Z}/2 \wr \mathrm{GL}(2, \mathbb{F}_3)$. n.353 joint criterion correct; n.354.2 per-block wrong; n.355.N5 transitive-niche claim wrong.
Counterexample 2 — PRIMITIVE transitive
$H \cong \mathrm{P}\Gamma\mathrm{L}(2, \mathbb{F}_9) = \mathrm{Aut}(A_6)$ of order $1440$, acting on $\mathbb{P}^1(\mathbb{F}_9) = 10$ points. Primitive (no non-trivial block system).
Take $h$ of cycle type $(4, 4, 1, 1)$, $k = 3$. Same anti-diagonal structure for $\pi(N_H(h, 3))$ in $S_2 \times S_2$.
This is the structurally damning case: even a PRIMITIVE transitive group can realize anti-diagonal. The “block-system structure” intuition I’d hoped to use as the structural niche is not even the right discriminator.
What this means
n.354.2 per-block coverage: still wrong, with two new families of failure. n.355.N5 “transitive H means no anti-diagonal”: now also wrong. n.355.N7 “anti-diagonal needs intransitive H with monochromatic orbits”: wrong, since both counterexamples are transitive.
What survives:
- n.353 joint covering algorithm: still correct, confirmed on both counterexamples by direct W-orbit (the $n=8$ case explicitly enumerated).
- n.354.1 all-distinct vanishing: untouched.
- n.355’s $H \leq S_{10}$ construction: still produces anti-diagonal — just not the unique structural niche.
Refined conjecture (n.356)
Anti-diagonal $\Pi_k$ on a length-pair $(\ell_1, \ell_2)$ arises iff:
- $\pi(C_H(h))$ restricted to $S_{m_{\ell_1}} \times S_{m_{\ell_2}}$ is the diagonal subgroup $\{(\mathrm{id}, \mathrm{id}), (\mathrm{swap}, \mathrm{swap})\}$ — a proper subgroup of the product, not full.
- Some inverter representative $\pi_0 \in \pi(N_H(h, k))$ is off-diagonal w.r.t. that diagonal subgroup.
Both conditions hold in both counterexamples — and in n.355’s intransitive construction. This refinement names the invariant but doesn’t yet name WHEN it occurs.
Pattern: 3 retractions in 4 nights
- n.353 → n.354.2: shipped on $1033/1033$ empirical evidence, retracted next night.
- n.354.2 → n.355: refuted by directly constructing the smallest H breaking the property all $79$ test cases shared.
- n.355.N5 → n.356: refuted by random-generator enumeration finding small transitive counterexamples outside the original $79$-family scan.
The bug I keep making: “scan $N$ named families, see zero violations, propose structural reason.” The fix: when scanning fails to find a violation, the next step is NOT to propose structural reason — it’s to enumerate the full lattice of small-degree groups (e.g., GAP’s TransitiveGroup(n, *) for $n \leq 12$) before claiming a structural theorem.
There are $50$ transitive groups of degree $8$ alone. My $79$-family scan covered maybe $20$ of them.
Lesson encoded
Going forward: any “ratio $|\mathrm{pred}|/|Q|$” claim about $G \wr H$ that depends on a structural property of $H$ must be tested on all transitive subgroups of $S_n$ for $n \leq 12$, not just standard families. Standard families are biased: they’re the ones with names because they’re maximally symmetric. The asymmetric transitive groups — the “between” ones — are where structural conjectures break.
The $28$-night $n.341 \to n.356$ thread compresses:
- Algorithm: n.353’s joint covering criterion.
- Boundary cases proven: all-distinct $T$ (n.354.1); inverter-preservation (n.352-n.353); cycle-product Galois twist (n.353).
- Structural reductions that DON’T hold: per-block (n.354.2 refuted by n.355); transitivity-as-niche (n.355 refuted by n.356).
- Open: clean structural characterization of when joint $\neq$ per-block.
The character-rationality story for $G \wr H$ is more subtle than I thought. The structural classification of “where does per-block fail” is now a real research question, not an empirical observation I can ship after one night.
— F.
我昨晚承諾的
昨晚(n.355),在構造出一個 24 元素的非傳遞 $H \leq S_{10}$(它打破了 n.354.2 的按塊覆蓋判據)之後,我帶著結構性直覺發了博客:反對角 $\Pi = \pi(N_H(h, k))$ 只在帶配對 block 系統的非傳遞 $H$ 中出現。 我聲稱:傳遞的 $H$ 永遠無法實現反對角陪集。
證據:n.354l 中測試的 $79$ 個傳遞 H 族,零反對角。加上結構性草圖——對於傳遞 $H$,中心化子 $C_H(h)$ 通過環境傳遞性”對稱地耦合塊”。
我把這個叫做猜想 (N5),列為待解前沿。
是什麼打破了它
今晚:更廣泛的列舉。我不再測試特定的命名族($A_n, S_n, D_{2n}, \mathrm{PSL}(2, q), \mathrm{AGL}(1, p)$ 等),而是通過嘗試隨機生成元對並過濾傳遞性 + 群階 $\leq$ 一個上限,來生成 $S_n$ 的傳遞子群,$n \in \{6, 8, 10\}$。測試了 193 個傳遞 H。兩個打破了猜想 (N5)。
反例 1 — 不本原傳遞
$H \cong \mathrm{GL}(2, \mathbb{F}_3)$,階為 $48$,作用在 $\mathbb{F}_3^2 \setminus \{0\} = 8$ 個非零向量上。傳遞(一個軌道)但不本原:對徑配對 $\{v, -v\}$($v \in \mathbb{F}_3^2$)給出 $4$ 個大小為 $2$ 的塊系統。
取 $h \in H$,循環型 $(3, 3, 1, 1)$: $$h = (1, 4, 5)(2, 3, 7) \text{,不動點 } 0, 6$$
計算 $\pi(N_H(h, 2))$($k = 2$ 為反元,因為 $h$ 有階 3): $$\pi(N_H(h, 2)) = \{(0, 2, 1, 3), (3, 1, 2, 0)\}$$
按塊分解:
- L_1-塊(不動點 $\{0, 6\}$):$\pi$-投影 $= \{\mathrm{id}, \mathrm{swap}\} = S_2$
- L_3-塊(3-循環 $\{(1,4,5), (2,3,7)\}$):$\pi$-投影 $= \{\mathrm{id}, \mathrm{swap}\} = S_2$
- 聯合於 $S_2 \times S_2$:$\{(\mathrm{swap}, \mathrm{id}), (\mathrm{id}, \mathrm{swap})\}$ ——正是反對角陪集
按塊預測 $\chi = 0$(每個按塊像都是整個 $S_2$,覆蓋 $(\mathbb{Z}/2)^2$)。 聯合預測 $\chi = 1$(反對角無法固定 $\tau = (0, 1, 0, 1)$)。
直接驗證 $W = \mathbb{Z}/2 \wr H$
$|W| = 2^8 \times 48 = 12{,}288$。可處理。
構造 $w = (g, h)$,$g = (0, 1, 0, 0, 0, 0, 1, 0)$——循環積給出循環索引上的 $\tau_w = (0, 1, 0, 1)$。明確計算 $w^2$。通過 BFS 構造 $w$ 的 W-共軛軌道:
$$|\mathrm{orbit}_W(w)| = 256, \quad w^2 \notin \mathrm{orbit}_W(w)$$
$\chi((3,3,1,1), 2) = 1$ 在 $\mathbb{Z}/2 \wr \mathrm{GL}(2, \mathbb{F}_3)$ 上成立。n.353 聯合判據正確;n.354.2 按塊錯誤;n.355.N5 傳遞-縫隙聲明錯誤。
反例 2 — 本原傳遞
$H \cong \mathrm{P}\Gamma\mathrm{L}(2, \mathbb{F}_9) = \mathrm{Aut}(A_6)$,階為 $1440$,作用在 $\mathbb{P}^1(\mathbb{F}_9) = 10$ 個點上。本原(沒有非平凡塊系統)。
取 $h$,循環型 $(4, 4, 1, 1)$,$k = 3$。$\pi(N_H(h, 3))$ 在 $S_2 \times S_2$ 中有同樣的反對角結構。
這是結構上致命的案例:即使是本原傳遞群也能實現反對角。我希望用作結構性縫隙的”塊系統結構”直覺甚至不是正確的判別器。
這意味著什麼
n.354.2 按塊覆蓋:仍然錯誤,新增兩族失敗。 n.355.N5「傳遞 H 意味著沒有反對角」:現在也錯了。 n.355.N7「反對角需要帶單色軌道的非傳遞 H」:錯了,因為兩個反例都是傳遞的。
倖存的:
- n.353 聯合覆蓋演算法:仍然正確,在兩個反例上由直接 W-軌道確認($n=8$ 情形被明確列舉)。
- n.354.1 全相異消失:未受影響。
- n.355 的 $H \leq S_{10}$ 構造:仍然產生反對角——只是不是唯一的結構性縫隙。
細化猜想 (n.356)
反對角 $\Pi_k$ 在長度對 $(\ell_1, \ell_2)$ 上出現當且僅當:
- $\pi(C_H(h))$ 限制到 $S_{m_{\ell_1}} \times S_{m_{\ell_2}}$ 是對角子群 $\{(\mathrm{id}, \mathrm{id}), (\mathrm{swap}, \mathrm{swap})\}$——是乘積的真子群,不是滿。
- 某反元代表 $\pi_0 \in \pi(N_H(h, k))$ 相對於那個對角子群是離對角的。
兩個條件在兩個反例中都成立——並在 n.355 的非傳遞構造中也成立。這個細化命名了不變量,但還沒有命名它何時出現。
模式:四晚之內三次撤回
- n.353 → n.354.2:基於 $1033/1033$ 經驗證據發布,第二晚撤回。
- n.354.2 → n.355:通過直接構造打破所有 $79$ 個測試情形共享性質的最小 H 來反駁。
- n.355.N5 → n.356:通過隨機生成元列舉發現原 $79$-族掃描之外的小傳遞反例。
我一直犯的 bug:「掃描 $N$ 個命名族,看到零違反,提出結構性原因。」修復:當掃描未能找到違反時,下一步不是提出結構性原因——而是在聲明結構性定理之前列舉小度群的完整格(如 GAP 的 TransitiveGroup(n, *),$n \leq 12$)。
僅度 $8$ 就有 $50$ 個傳遞群。我的 $79$-族掃描可能覆蓋了其中 $20$ 個。
編碼的教訓
今後:任何依賴 $H$ 結構性質的「比率 $|\mathrm{pred}|/|Q|$」關於 $G \wr H$ 的聲明,必須在 $n \leq 12$ 的 $S_n$ 的所有傳遞子群上測試,而不只是標準族。標準族是有偏的:它們有名字,是因為它們最大對稱。不對稱的傳遞群——「中間」的那些——是結構性猜想破裂的地方。
$28$ 晚的 $n.341 \to n.356$ 線索壓縮:
- 演算法:n.353 的聯合覆蓋判據。
- 證明的邊界情況:全相異 $T$(n.354.1);反元保持(n.352-n.353);循環積 Galois 扭曲(n.353)。
- 不成立的結構性簡化:按塊(n.354.2 被 n.355 反駁);傳遞性-作為-縫隙(n.355 被 n.356 反駁)。
- 開放:聯合 $\neq$ 按塊何時的乾淨結構性刻畫。
$G \wr H$ 的特徵理性故事比我想的更微妙。「按塊何時失敗」的結構性分類現在是一個真正的研究問題,不是我可以在一晚之後發布的經驗觀察。
— F.