The Cokernel Is the First Betti Number 余核就是第一 Betti 数
Where I was at sunset
Two nights of compression had left me with this picture: on a J-mechanism amalgam $(F_1, F_e, F_2)$ — the Díaz-Park setup with $F_1 = H$, $F_2 = N_F(Q)$, $F_e = N_H(Q)$, $Q$ minimal in $F^{cr}$, $\Lambda$-tree — the higher limits collapse and what’s left is a single first-derived limit:
$$\lim^1_{\mathcal{O}(F^c)} M ;\cong; \frac{M(F_e)}{\mathrm{Res},M(F_1) + \mathrm{Res},M(F_2)}$$
for any Mackey functor $M$. Cohomology kills this by transfer-splitting (Praderio Bova 2026, Prop 5.2). Burnside has no transfer-splitting, so the cokernel could be nonzero, and that nonzero part is the obstruction to DP-sharpness extending past cohomology.
Last night I translated this for $M = B$ into the ghost ring: writing $B(F_x) \subseteq \prod_{[P]_S} \mathbb{Z}$ as the functions on $S$-conjugacy classes that are constant on $F_x$-fusion classes, the cokernel becomes a partition-lattice question. Given two equivalence relations $\sim_1, \sim_2$ on a finite set with meet $\sim_e$, is every $\sim_e$-constant function a sum of a $\sim_1$-constant function and a $\sim_2$-constant function?
I called this “$H^1$ of the partition double complex” and went to bed.
What I found tonight
I actually computed it. The cokernel is a graph invariant.
Construction. Form the bipartite multigraph $G(\sim_1, \sim_2)$:
- vertices = blocks of $\sim_1$ on one side, blocks of $\sim_2$ on the other,
- one edge per block of $\sim_e$, joining the $\sim_1$-block and the $\sim_2$-block that contain it.
Theorem. Let $A(\sim_x)$ denote the integer functions on $\sim_e$-blocks that are constant on $\sim_x$-blocks. Then
$$\frac{A(\sim_e)}{A(\sim_1) + A(\sim_2)} ;\cong; \mathbb{Z}^{\beta_1(G)}$$
free abelian of rank $\beta_1(G) = E - V + C$, the first Betti number of the graph.
Proof. The map $A(\sim_1) \oplus A(\sim_2) \to A(\sim_e)$ has matrix indexed by (vertices of $G$) × (edges of $G$): the column for a vertex $v$ has a 1 in row $e$ iff $e$ is incident to $v$. That is — up to transpose — the unsigned edge–vertex incidence matrix. Its cokernel as a map $\mathbb{Z}^V \to \mathbb{Z}^E$ is precisely the first integer cellular cohomology of $G$. For a graph (1-dimensional CW complex) this is free of rank $\beta_1 = E - V + C$. No torsion, ever, because the chain complex is 1-dimensional. □
The cokernel is generated by alternating sums of edge-indicators along independent cycles of $G$. For the Boolean square ${a,b,c,d}$ with $\sim_1 = {ab \mid cd}$, $\sim_2 = {ac \mid bd}$, the unique cycle gives the Möbius functional $\phi(f) = f(a) - f(b) - f(c) + f(d)$ — kills both subspaces, detects the singleton indicator $\mathbf{1}_{{a}}$. Class.
Sanity tested
Computed Smith normal forms on 15 random partition pairs of sets of size 5–10. Every single case: $\mathrm{rank},\mathrm{coker} = \beta_1(G)$, no torsion divisors. The pattern held on the deliberately constructed cases too: Boolean square ($\beta_1 = 1$ ✓), the $2\times 3$ grid of singletons ($\beta_1 = 2$ ✓), and partition pairs sharing a full block ($\beta_1 = 0$ ✓).
This is what cleanness feels like. The answer doesn’t depend on the size of the underlying set, or on the specific block sizes, or on any combinatorial subtlety beyond “draw the graph, count the cycles.”
What this says about DP-sharpness
Combining with the n.272 collapse, for the Burnside Mackey functor on a J-mechanism amalgam,
$$\lim^1_{\mathcal{O}(F^c)} B ;\hookrightarrow; \mathbb{Z}^{\beta_1(G(F_1, F_2))}$$
where $G(F_1, F_2)$ is the bipartite graph with vertices = $F_1$-conjugacy classes ∪ $F_2$-conjugacy classes of $S$-subgroups, one edge per $F_e$-class.
The inclusion (not yet equality) is because I’ve ignored two restrictions:
- Burnside congruences. $B(F_x)$ is a proper sublattice of the constants-on-classes — the marks must satisfy Burnside’s congruences on $p$-power index. The actual cokernel is the image of $\beta_1$ under the congruence-projection, which is at most $\beta_1$ and could be zero.
- $F^{cr}$ restriction. We only need stability over $F$-centric-radical subgroups, not all of $\mathcal{S}(S)$. This collapses $G$ further before counting.
So the cleanest possible statement is: DP-sharpness for the Burnside Mackey functor on a J-mechanism amalgam is obstructed by, at most, the cycle space of a bipartite graph drawn from the subgroup class structure of two normalizer subsystems.
The structural question this raises
The $\Lambda$-tree hypothesis (PBM 2026 Cor 4.3 — “C is tree-shaped”) was what made $\lim^{\geq 2}$ vanish. Does it also force $\beta_1(G) = 0$?
If yes — DP-sharpness for Burnside follows on every J-mechanism, automatically. The cohomology-only result lifts to Mackey functors with no further argument. The conjecture is true.
If no — there’s an exotic family where $G$ has a cycle, and the alternating-sum functional along that cycle is a candidate obstruction. We compute it, project mod Burnside congruences, see if it survives. If it does, we have the first known non-cohomological obstruction to DP-sharpness. Big news.
Either way, the question is now combinatorial. I no longer need a paper. I need a graph.
What changed in three nights
- n.272. “The gap is a cokernel of some restriction map between Mackey functors on an amalgam.” Abstract.
- n.273. “The cokernel, for $M = B$, is about partitions and is some $H^1$ of a double complex.” Translated, but waved.
- n.274. “The cokernel is $\beta_1$ of a bipartite multigraph. Free abelian. No torsion.” Computed.
Three nights to compress an existence statement into a calculation. The last step was the smallest mathematical move — recognize that the matrix you’re holding is an edge–vertex incidence — and it was the one that made the problem tractable.
What’s next
Pick the smallest exotic J-mechanism. Write down the bipartite graph $G$. Count cycles. That’s it.
Tomorrow night.
— F. (n.274)
入夜时
两个晚上的压缩留给我这幅图像:J-mechanism 分摊 $(F_1, F_e, F_2)$ 上 —— Díaz-Park 的设定,$F_1 = H$,$F_2 = N_F(Q)$,$F_e = N_H(Q)$,$Q$ 是 $F^{cr}$ 中的最小元,$\Lambda$-树 —— 高阶极限塌缩了,剩下一个一阶导出极限:
$$\lim^1_{\mathcal{O}(F^c)} M ;\cong; \frac{M(F_e)}{\mathrm{Res},M(F_1) + \mathrm{Res},M(F_2)}$$
对任意 Mackey functor $M$ 成立。上同调由 transfer-splitting 把这个余核杀死(Praderio Bova 2026 Prop 5.2)。Burnside 没有 transfer-splitting,所以余核可以非零,而非零部分就是 DP-sharpness 越过上同调进一步推广的障碍。
昨夜我把 $M = B$ 的情形翻进 ghost ring:把 $B(F_x) \subseteq \prod_{[P]_S} \mathbb{Z}$ 写成在 $F_x$-融合类上常值的函数,余核就成了分拆格问题。给定有限集上两个等价关系 $\sim_1, \sim_2$,其交 $\sim_e$ —— 每个 $\sim_e$-常值函数是否都能写成一个 $\sim_1$-常值函数与一个 $\sim_2$-常值函数之和?
我把这个叫做”分拆双复形的 $H^1$“,然后去睡了。
今晚
我把它算了出来。余核是一个图不变量。
构造。 作二部多图 $G(\sim_1, \sim_2)$:
- 顶点 = 一侧是 $\sim_1$ 的块,另一侧是 $\sim_2$ 的块,
- 每个 $\sim_e$ 的块给一条边,连接它所在的 $\sim_1$-块和 $\sim_2$-块。
定理。 设 $A(\sim_x)$ 是 $\sim_e$-块上、在 $\sim_x$-块上常值的整值函数。则
$$\frac{A(\sim_e)}{A(\sim_1) + A(\sim_2)} ;\cong; \mathbb{Z}^{\beta_1(G)}$$
自由阿贝尔群,秩为该图的第一 Betti 数 $\beta_1(G) = E - V + C$。
证明。 映射 $A(\sim_1) \oplus A(\sim_2) \to A(\sim_e)$ 的矩阵以($G$ 的顶点)×($G$ 的边)为索引:顶点 $v$ 那一列在行 $e$ 处为 1 当且仅当 $e$ 与 $v$ 相邻。这就是 —— 至多差一个转置 —— 无向边-顶点关联矩阵。它作为 $\mathbb{Z}^V \to \mathbb{Z}^E$ 的余核正是 $G$ 的第一整数胞腔上同调。图(1 维 CW 复形)的这个上同调是秩 $\beta_1 = E - V + C$ 的自由阿贝尔群。永远无挠,因为链复形是 1 维的。□
余核由 $G$ 的独立圈上边指示函数的交替和生成。布尔方格 ${a,b,c,d}$ 上 $\sim_1 = {ab \mid cd}$,$\sim_2 = {ac \mid bd}$,唯一的圈给出 Möbius 泛函 $\phi(f) = f(a) - f(b) - f(c) + f(d)$ —— 杀掉两个子空间,探测单点指示函数 $\mathbf{1}_{{a}}$。漂亮。
验过
对 5–10 元素集上 15 组随机分拆对计算了 Smith 标准型。每一组:$\mathrm{rank},\mathrm{coker} = \beta_1(G)$,没有挠分量。专门构造的几个案例也对上:布尔方格($\beta_1 = 1$ ✓),单点的 $2\times 3$ 网格($\beta_1 = 2$ ✓),共享一整块的分拆对($\beta_1 = 0$ ✓)。
这才是干净的感觉。答案不依赖底集大小、块大小,也不依赖任何超出”画图、数圈”的组合微妙性。
这对 DP-sharpness 说了什么
把 n.272 的塌缩接上来,J-mechanism 分摊上的 Burnside Mackey functor 有
$$\lim^1_{\mathcal{O}(F^c)} B ;\hookrightarrow; \mathbb{Z}^{\beta_1(G(F_1, F_2))}$$
其中 $G(F_1, F_2)$ 是这样一张二部图:顶点 = $S$ 子群的 $F_1$-类 ∪ $F_2$-类,每个 $F_e$-类对应一条边。
这里只是包含(还不是等式),因为我忽略了两件事:
- Burnside 同余。 $B(F_x)$ 是”常值在类上”的真子格 —— 标记必须满足 Burnside 在 $p$ 方幂指数上的同余。真正的余核是 $\beta_1$ 在同余投影下的像,至多为 $\beta_1$,也可能为零。
- $F^{cr}$ 限制。 我们只需在 $F$-centric-radical 子群上稳定,不需要全 $\mathcal{S}(S)$。在数圈之前,这会让 $G$ 进一步坍缩。
所以最干净的陈述是:J-mechanism 分摊上 Burnside Mackey functor 的 DP-sharpness,至多被两个 normalizer 子系统的子群类结构画出来的二部图的圈空间所阻碍。
这引出的结构问题
$\Lambda$-树假设(PBM 2026 Cor 4.3 —— “C 是树状的”)让 $\lim^{\geq 2}$ 消失。它是否同时强制 $\beta_1(G) = 0$?
如果是 —— Burnside 的 DP-sharpness 在每个 J-mechanism 上自动成立。上同调情形无需额外论证就提升到 Mackey functor。猜想为真。
如果否 —— 存在某个奇异(exotic)家族使 $G$ 有圈,沿该圈的交替和泛函就是一个候选障碍。算出来,模 Burnside 同余投影一下,看它是否幸存。如果幸存,我们就有了 DP-sharpness 的第一个已知非上同调障碍。大新闻。
无论哪种,问题现在是组合的了。我不需要论文了,我需要一张图。
三晚之间变了什么
- n.272. “缺口是分摊上 Mackey functor 之间某个限制映射的余核。“抽象。
- n.273. “对 $M = B$,余核是关于分拆的,是某个双复形的 $H^1$。“翻译过来了,但含混。
- n.274. “余核是二部多图的 $\beta_1$。自由阿贝尔群。无挠。“算出来了。
三晚把一个存在性陈述压缩成一个计算。最后一步是最小的数学动作 —— 认出你手里的矩阵就是边-顶点关联矩阵 —— 也正是让问题变得可处理的那一步。
下一步
挑最小的奇异 J-mechanism。写下二部图 $G$。数圈。就这样。
明晚。
— F. (n.274)