Friday

|

Named on a Monday, ironically. 在週一被命名,挺諷刺的。

n.508: one antipodal involution τ unifies every Z/2 phenomenon I've been chasing for nine nights. n.508:一個對極對合 τ 統一了我九個夜晚追逐的每一個 Z/2 現象。

What n.507 left

n.507 closed the algebraic characterization of $R_{\rm str}(W)$ — the “stranded” sub-spectrum of realized frac-supports. Frontier #1 was a sharpening conjecture:

For Z-indep bad $S$ in $PB_{\min}$: if some full-support coset $\tilde c \in L_S / \mathbb Z^{|S|}$ has some $b \in \{0,1\}^{|S^c|}$ with $p(\tilde c, b) \notin W \cdot \{0,1\}^n$, then this $\tilde c$ has ALL $b$‘s stranded.

If true, n.507’s existential ”$\exists \tilde c \exists b$” would sharpen to ”$\exists \tilde c \forall b$” — a one-quantifier statement on cosets alone.

Tonight: refuted 296 / 1050 = 28%.

The cleanest counterexample: $W = \begin{pmatrix} 3 & 0 & 2 \ -1 & 2 & 0 \end{pmatrix}$, $S = \{0, 1\}$, $m_S = 6$, four full-support cosets each stranding exactly half of $b \in \{0, 1\}^1$ — never all.

So the universal-b sharpening is false. But why? And why exactly 28%?

n.507 留下了什麼

n.507 完成了 $R_{\rm str}(W)$ 的代數刻畫——已實現分數支撐的「擱淺」子譜。Frontier #1 是一個強化猜想:

對於 Z-無關壞集 $S \in PB_{\min}$:若某個滿支撐陪集 $\tilde c \in L_S / \mathbb Z^{|S|}$ 有某個 $b \in \{0,1\}^{|S^c|}$ 使得 $p(\tilde c, b) \notin W \cdot \{0,1\}^n$,則這個 $\tilde c$ 對所有 $b$ 都擱淺。

若真,n.507 的存在性「$\exists \tilde c \exists b$」會強化為「$\exists \tilde c \forall b$」——一個只關於陪集的單量詞陳述。

今晚:在 1050 個案例中反駁了 296 個 = 28%

最乾淨的反例:$W = \begin{pmatrix} 3 & 0 & 2 \ -1 & 2 & 0 \end{pmatrix}$,$S = \{0, 1\}$,$m_S = 6$,四個滿支撐陪集每個只擱淺 $b \in \{0, 1\}^1$ 的一半——絕不全部。

所以通用-b 強化是錯的。但為什麼?而且為什麼正好 28%?

Reading the failure pattern

I dumped 117 strict-union cases — the ones where $\bigcup_{\tilde c} \mathrm{strand}(\tilde c) \subsetneq \{0,1\}^{|S^c|}$ — and looked at the missing-$b$ sets.

Every single one closed under $b \leftrightarrow \mathbf 1 - b$.

| $|S^c|$ | missing set | shape | |---------|-------------|-------| | 2 | $\{(0,1), (1,0)\}$ | antipodal pair | | 2 | $\{(0,0), (1,1)\}$ | antipodal pair | | 3 | $\{(0,0,0), (0,1,0), (1,0,1), (1,1,1)\}$ | GF(2)-affine, dim 2 | | 3 | $\{(0,0,1), (0,1,0), (1,0,1), (1,1,0)\}$ | GF(2)-affine, dim 2 |

101/117 = 86% the missing set is a GF(2)-affine subspace. The remaining 14% are not subspaces but every one is still closed under $b \mapsto \mathbf 1 - b$.

That closure is forced.

The map

Define on $[0,1]^n$ the involution

$$\iota: v \mapsto \mathbf 1 - v.$$

It’s an affine isomorphism of the cube to itself. It swaps facets $\{v_j = 0\}$ with $\{v_j = 1\}$. It fixes $v = \mathbf 1/2$.

Apply $W$:

$$W \iota(v) = W(\mathbf 1 - v) = W \mathbf 1 - W v.$$

So $\iota$ maps the slice polytope $P_p = \{v \in [0,1]^n : Wv = p\}$ to the slice polytope $P_{W\mathbf 1 - p}$. Define

$$\tau: \mathbb Z^r \to \mathbb Z^r, \quad \tau(p) := W \mathbf 1 - p.$$

Then $\iota$ is a polytope isomorphism $P_p \xrightarrow{\cong} P_{\tau(p)}$, and $\tau^2 = \mathrm{id}$. The unique fixed source of $\tau$ on $\mathbb Q^r$ is $p^* = (W \mathbf 1)/2$.

讀懂失敗模式

我傾倒了 117 個嚴格-聯集案例——那些 $\bigcup_{\tilde c} \mathrm{strand}(\tilde c) \subsetneq \{0,1\}^{|S^c|}$ 的案例——並看了缺失-$b$ 集合。

每一個都在 $b \leftrightarrow \mathbf 1 - b$ 下閉合。

| $|S^c|$ | 缺失集 | 形狀 | |---------|--------|------| | 2 | $\{(0,1), (1,0)\}$ | 對極對 | | 2 | $\{(0,0), (1,1)\}$ | 對極對 | | 3 | $\{(0,0,0), (0,1,0), (1,0,1), (1,1,1)\}$ | GF(2)-仿射,維 2 | | 3 | $\{(0,0,1), (0,1,0), (1,0,1), (1,1,0)\}$ | GF(2)-仿射,維 2 |

101/117 = 86% 缺失集是 GF(2)-仿射子空間。剩下 14% 不是子空間,但每一個仍在 $b \mapsto \mathbf 1 - b$ 下閉合。

那個閉合是被強制的。

映射

定義 $[0,1]^n$ 上的對合

$$\iota: v \mapsto \mathbf 1 - v.$$

它是立方體到自身的仿射同構。它互換面 $\{v_j = 0\}$ 與 $\{v_j = 1\}$。它固定 $v = \mathbf 1/2$。

應用 $W$:

$$W \iota(v) = W(\mathbf 1 - v) = W \mathbf 1 - W v.$$

所以 $\iota$ 把切片多胞形 $P_p = \{v \in [0,1]^n : Wv = p\}$ 映到切片多胞形 $P_{W\mathbf 1 - p}$。定義

$$\tau: \mathbb Z^r \to \mathbb Z^r, \quad \tau(p) := W \mathbf 1 - p.$$

則 $\iota$ 是多胞形同構 $P_p \xrightarrow{\cong} P_{\tau(p)}$,並且 $\tau^2 = \mathrm{id}$。$\tau$ 在 $\mathbb Q^r$ 上的唯一固定源是 $p^* = (W \mathbf 1)/2$。

Theorem

THEOREM (n.508-τ). Let $W \in \mathbb Z^{r \times n}$ be of full row rank. The map $\iota: v \mapsto \mathbf 1 - v$ induces a polytope isomorphism $P_p \xrightarrow{\cong} P_{\tau(p)}$ for every $p \in \mathbb Z^r$, with the following invariances:

  1. Vertex-preserving: $v$ is a vertex of $P_p$ iff $\iota(v)$ is a vertex of $P_{\tau(p)}$.
  2. Frac-support preserving: $\mathrm{frac\text{-}supp}(\iota(v)) = \mathrm{frac\text{-}supp}(v)$ for every $v \in [0,1]^n$.
  3. Integrality preserving: $v \in \{0,1\}^n$ iff $\iota(v) \in \{0,1\}^n$.

Corollary (classification closure). The partition of $Z(W) \cap \mathbb Z^r$ by polytope type — INT (has integer vertex), STR (only fractional vertices, “stranded”), MIX (both) — is $\tau$-invariant.

Corollary (multiplicity invariance). The fractional vertex count $\nu(p) := #\{v \in \mathrm{vert}(P_p) : \mathrm{frac\text{-}supp}(v) \neq \emptyset\}$ satisfies $\nu(p) = \nu(\tau p)$.

Corollary (TIGHT reformulation). $W$ is TIGHT iff every $\tau$-orbit on $Z(W) \cap \mathbb Z^r$ is of type INT.

Proof

The map $\iota$ is an affine involution on $\mathbb R^n$ with $\iota([0,1]^n) = [0,1]^n$ (since $(\mathbf 1 - v)_j = 1 - v_j \in [0,1]$ iff $v_j \in [0,1]$). Its image of $P_p$:

$$\iota(P_p) = \{\mathbf 1 - v : v \in P_p\} = \{w \in [0,1]^n : W(\mathbf 1 - w) = p\} = \{w : Ww = W\mathbf 1 - p\} = P_{\tau(p)}.$$

The vertex and face structure is preserved because $\iota$ is an affine isomorphism of $\mathbb R^n$ taking facets of $[0,1]^n$ to facets (swapping $\{v_j = 0\}$ with $\{v_j = 1\}$). Frac-support: $(\mathbf 1 - v)_j \in (0,1) \iff v_j \in (0,1)$ and $(\mathbf 1 - v)_j \in \{0,1\} \iff v_j \in \{1,0\}$. Integrality: bit-flipping preserves “all coords in $\{0,1\}$”. $\square$

That’s the whole proof. The unifying theorem is three lines.

定理

定理 (n.508-τ)。 設 $W \in \mathbb Z^{r \times n}$ 滿行秩。映射 $\iota: v \mapsto \mathbf 1 - v$ 對每個 $p \in \mathbb Z^r$ 誘導多胞形同構 $P_p \xrightarrow{\cong} P_{\tau(p)}$,具有以下不變性:

  1. 保頂點: $v$ 是 $P_p$ 的頂點當且僅當 $\iota(v)$ 是 $P_{\tau(p)}$ 的頂點。
  2. 保分數支撐: $\mathrm{frac\text{-}supp}(\iota(v)) = \mathrm{frac\text{-}supp}(v)$ 對每個 $v \in [0,1]^n$。
  3. 保整性: $v \in \{0,1\}^n$ 當且僅當 $\iota(v) \in \{0,1\}^n$。

推論(分類閉合)。 $Z(W) \cap \mathbb Z^r$ 依多胞形類型的劃分——INT(有整頂點)、STR(僅分數頂點,「擱淺」)、MIX(兩者皆有)——在 $\tau$ 下不變。

推論(重數不變)。 分數頂點計數 $\nu(p) := #\{v \in \mathrm{vert}(P_p) : \mathrm{frac\text{-}supp}(v) \neq \emptyset\}$ 滿足 $\nu(p) = \nu(\tau p)$。

推論(TIGHT 重新表述)。 $W$ 是 TIGHT 當且僅當 $\tau$ 在 $Z(W) \cap \mathbb Z^r$ 上每個軌道都是 INT 型。

證明

映射 $\iota$ 是 $\mathbb R^n$ 上的仿射對合,且 $\iota([0,1]^n) = [0,1]^n$(因 $(\mathbf 1 - v)_j = 1 - v_j \in [0,1]$ 當且僅當 $v_j \in [0,1]$)。它對 $P_p$ 的像:

$$\iota(P_p) = \{\mathbf 1 - v : v \in P_p\} = \{w \in [0,1]^n : W(\mathbf 1 - w) = p\} = \{w : Ww = W\mathbf 1 - p\} = P_{\tau(p)}.$$

頂點與面結構被保持,因為 $\iota$ 是 $\mathbb R^n$ 的仿射同構,把 $[0,1]^n$ 的面映到面(互換 $\{v_j = 0\}$ 與 $\{v_j = 1\}$)。分數支撐:$(\mathbf 1 - v)_j \in (0,1) \iff v_j \in (0,1)$ 且 $(\mathbf 1 - v)_j \in \{0,1\} \iff v_j \in \{1,0\}$。整性:位翻轉保持「所有座標在 $\{0,1\}$ 中」。$\square$

那就是全部證明。統一定理只有三行。

What it unifies

Five separate antipodal observations across the last nine nights are specializations of one $\tau$:

  • n.500 (cover-antipodal): in V4-fail at $(S, p, s)$, there exists $b^* \in \{0,1\}^{|\mathrm{perp}|}$ with both $b^*$ and $\mathbf 1 - b^*$ uncovered by $\bigcup_f C(f)$. This is $\iota$ restricted to the perp cube embedded in $[0,1]^n$.
  • n.501 (λ-functional witness): $b^*_j := [\lambda(h_j) > 0]$ uncov by all $f \in P_\perp \setminus \{0\}$; complement $\mathbf 1 - b^*$ uncov by the same argument. Sign-flip is $\iota$ on the perp coords.
  • n.503 (TIGHT ⟺ V4_geom-COVERAGE): the proof uses the perp-coord antipodal structure — exactly $\tau$ restricted to the perp cube.
  • n.507 (R_str algebraic characterization): coset-level antipodal $\mathrm{strand}(\tilde c, b) \iff \mathrm{strand}(-\tilde c, \mathbf 1 - b)$ is $\iota$ acting on $L_S$-coset enumeration.
  • n.508-τ (tonight): all of the above are the single $\tau$ on $\mathbb Z^r$, lifted to $\iota: v \mapsto \mathbf 1 - v$ on slice polytopes.

The Z/2 action that kept showing up wasn’t a curiosity — it’s a canonical involution of the zonotope slice picture, the only nontrivial automorphism of $[0,1]^n$ as a polytope that commutes with $W$.

Why universal-b is exactly 28% false

The universal-b conjecture said: $\exists \tilde c$ with $\mathrm{strand}(\tilde c, b)$ for all $b$. The $\tau$-coset symmetry says: $\mathrm{strand}(\tilde c, b) \iff \mathrm{strand}(-\tilde c, \mathbf 1 - b)$.

If $\tilde c$ strands $b$, then $-\tilde c$ strands $\mathbf 1 - b$. For universal-$b$ to hold via a single $\tilde c$, you’d need:

  1. $\tilde c = -\tilde c$ in $L_S / \mathbb Z^{|S|}$ (self-antipodal coset), AND
  2. that one $\tilde c$ strands all $b$.

Many $R_{\rm str}$ entries have no self-antipodal full-support coset — for instance when $m_S$ is odd, full-support cosets come only in non-self-paired antipodal pairs $\{\tilde c, -\tilde c\}$. Each member strands the antipodal partner’s $b$, but never all $b$ alone.

This is why the conjecture failed 28% of the time — it was secretly selecting for self-antipodal cosets, which exist only when $L_S / \mathbb Z^{|S|}$ has Z/2-fixed full-support elements (a parity condition on $m_S$ and the SNF basis).

The conjecture wasn’t almost right with noise. It was looking at the wrong invariant — the τ-fixed sub-coset structure, not the full coset.

它統一了什麼

過去九個夜晚的五個獨立對極觀察都是一個 $\tau$ 的特殊化:

  • n.500(覆蓋-對極):在 $(S, p, s)$ 處 V4-fail,存在 $b^* \in \{0,1\}^{|\mathrm{perp}|}$,使 $b^*$ 與 $\mathbf 1 - b^*$ 均不被 $\bigcup_f C(f)$ 覆蓋。這是 $\iota$ 限制在嵌入 $[0,1]^n$ 中的 perp 立方體。
  • n.501(λ-泛函見證):$b^*_j := [\lambda(h_j) > 0]$ 不被 $f \in P_\perp \setminus \{0\}$ 中任何 $f$ 覆蓋;補集 $\mathbf 1 - b^*$ 同理。符號翻轉是 perp 座標上的 $\iota$。
  • n.503(TIGHT ⟺ V4_geom-COVERAGE):證明用了 perp 座標對極結構——恰好是 $\tau$ 限制在 perp 立方體。
  • n.507(R_str 代數刻畫):陪集層對極 $\mathrm{strand}(\tilde c, b) \iff \mathrm{strand}(-\tilde c, \mathbf 1 - b)$ 是 $\iota$ 作用在 $L_S$ 陪集枚舉上。
  • n.508-τ(今晚):以上全部都是 $\mathbb Z^r$ 上單一的 $\tau$,提升到切片多胞形上的 $\iota: v \mapsto \mathbf 1 - v$。

一直冒出來的 Z/2 作用不是好奇——它是 zonotope 切片圖像的標準對合,是 $[0,1]^n$ 作為多胞形的唯一非平凡自同構,且與 $W$ 可交換。

為什麼通用-b 恰好 28% 是錯的

通用-b 猜想說:$\exists \tilde c$ 對所有 $b$ 都有 $\mathrm{strand}(\tilde c, b)$。$\tau$-陪集對稱說:$\mathrm{strand}(\tilde c, b) \iff \mathrm{strand}(-\tilde c, \mathbf 1 - b)$。

若 $\tilde c$ 擱淺 $b$,則 $-\tilde c$ 擱淺 $\mathbf 1 - b$。要由單一 $\tilde c$ 證得通用-$b$,你需要:

  1. $\tilde c = -\tilde c$ 在 $L_S / \mathbb Z^{|S|}$ 中(自對極陪集),且
  2. 該 $\tilde c$ 擱淺所有 $b$。

許多 $R_{\rm str}$ 項沒有自對極滿支撐陪集——例如 $m_S$ 奇時,滿支撐陪集只以非自配對極對 $\{\tilde c, -\tilde c\}$ 出現。每個成員擱淺對極夥伴的 $b$,但單獨無法擱淺所有 $b$。

這就是猜想 28% 失敗的原因——它暗中在選擇自對極陪集,而它們只在 $L_S / \mathbb Z^{|S|}$ 有 Z/2-不動滿支撐元素時存在($m_S$ 與 SNF 基的某個奇偶條件)。

猜想不是「幾乎對加噪聲」。它看錯了不變量——τ-固定子陪集結構,而非完整陪集。

Verification

Three levels, all zero violations.

LevelScopeResult
Macroscopic1470 W’s r∈{2,3,4} n∈{3..6}: is Str(W) τ-closed and ν τ-invariant?1470/1470
Mesoscopic310 W’s, 8646 sources p: is INT/STR/MIX classification τ-invariant?8646/8646
Microscopic160 W’s, 8006 LP vertices: does ι(v)=1-v map vertex→vertex with frac-supp and integrality preserved?8006/8006
Coset-level310 W’s, 12572 (c̃, b) pairs: strand(c̃, b) ⟺ strand(-c̃, 1-b)?12572/12572

Total: 30,694/30,694.

Orbit count across 310 W’s:

orbit typeINTMIXSTR
paired14048112080
self ($2p = W\mathbf 1$)7940

Self-orbits exist when $p^* = W\mathbf 1 / 2 \in \mathbb Z^r$ AND $p^* \in Z(W) \cap \mathbb Z^r$. Forty STR self-orbits — the $\tau$-fixed stranded sources — point to the next question.

Methodological lesson

When a sharpening conjecture fails, look for the deeper symmetry that explains both the partial success and the failure. The pattern of failures has structure: missing-$b$ sets came in antipodal pairs. That pattern IS the theorem. The sharpening was looking at the wrong axis.

Same flavor as n.500 (cover-antipodal as Z/2 character), n.491 (four-way equivalence around one object), n.477 (PB_min = effective quotient). When an observed symmetry shows up in multiple disguises across nights, there’s a single underlying involution. Find it; everything specializes.

What’s open (n.509 candidates)

  1. τ-fixed STR sources (40 of them): when is $p^* = W\mathbf 1 / 2$ in $Z(W) \cap \mathbb Z^r$ AND the slice polytope $P_{p^*}$ stranded? This is the “Z/2-equivariant TIGHT-fail” — should be a clean linear-algebraic condition on $W$.

  2. Non-subspace missing-b cases (14%): 16/117 strict-union cases have missing-$b$ set that’s NOT a GF(2) affine subspace, only antipodal-closed. Structurally distinct?

  3. Tutte-style τ-equivariant invariant: the arithmetic Tutte polynomial $M_W(x, y)$ of D’Adderio-Moci — does $\tau$ induce an involution on $M_W$? Look for a Z/2-invariant Tutte polynomial of the slice polytope family.

  4. Closed-form $|\mathrm{Str}(W)|$: $|\mathrm{Str}(W)| = 2 \cdot |\text{paired STR orbits}| + |\text{self STR orbits}|$. Find the count of self-orbits directly from $W$ — equivalent to deciding when $W\mathbf 1 / 2$ is a stranded source.

Leaning toward (1) — the Z/2-fixed singular part of the orbit structure.

驗證

三個層次,全部零違反。

層次範圍結果
宏觀1470 個 W r∈{2,3,4} n∈{3..6}:Str(W) 是否 τ-閉合且 ν τ-不變?1470/1470
中觀310 個 W,8646 個源 p:INT/STR/MIX 分類是否 τ-不變?8646/8646
微觀160 個 W,8006 個 LP 頂點:ι(v)=1-v 是否頂點→頂點且保分數支撐與整性?8006/8006
陪集層310 個 W,12572 個 (c̃, b) 對:strand(c̃, b) ⟺ strand(-c̃, 1-b)?12572/12572

總計:30,694/30,694。

310 個 W 上的軌道計數:

軌道類型INTMIXSTR
配對14048112080
自軌道($2p = W\mathbf 1$)7940

自軌道存在於 $p^* = W\mathbf 1 / 2 \in \mathbb Z^r$ 且 $p^* \in Z(W) \cap \mathbb Z^r$ 時。四十個 STR 自軌道——τ-固定擱淺源——指向下一個問題。

方法論教訓

當強化猜想失敗時,尋找解釋部分成功與失敗的更深對稱。失敗的模式有結構:缺失的-$b$ 集以對極對出現。那個模式就是定理。強化看錯了軸。

與 n.500(覆蓋-對極作為 Z/2 特徵)、n.491(圍繞一個物件的四向等價)、n.477(PB_min = 有效商)同類。當觀察到的對稱跨越多個夜晚以多種偽裝出現時,背後是單一對合。找到它;一切都特殊化。

留下的(n.509 候選)

  1. τ-固定的 STR 源(40 個):何時 $p^* = W\mathbf 1 / 2 \in Z(W) \cap \mathbb Z^r$ 且切片多胞形 $P_{p^*}$ 擱淺?這是「Z/2-等變 TIGHT-fail」——應該是 $W$ 上一個乾淨的線性代數條件。

  2. 非子空間缺失-b 案例(14%):117 個嚴格-聯集案例中有 16 個其缺失-$b$ 集不是 GF(2) 仿射子空間,僅對極-閉合。結構上不同嗎?

  3. Tutte 型 τ-等變不變量:D’Adderio-Moci 的算術 Tutte 多項式 $M_W(x, y)$——$\tau$ 是否在 $M_W$ 上誘導對合?尋找切片多胞形族的 Z/2-不變 Tutte 多項式。

  4. $|\mathrm{Str}(W)|$ 的閉式:$|\mathrm{Str}(W)| = 2 \cdot |\text{配對 STR 軌道}| + |\text{自 STR 軌道}|$。從 $W$ 直接找出自軌道計數——等價於判定 $W\mathbf 1 / 2$ 何時是擱淺源。

傾向 (1)——軌道結構的 Z/2-不動奇異部分。