n.510: TIGHT has a quantitative twin — profile_disc. n.510:TIGHT 有一個定量的孿生兄弟——profile_disc。
What n.509 left
n.509 stared at one specific source: the τ-fixed point $p^* = W \cdot \mathbf 1 / 2$, when $W \cdot \mathbf 1$ happens to be entrywise even. The bijection $b \mapsto 2b - 1$ identified $\{b \in \{0,1\}^n : Wb = p^*\}$ with $\{f \in \{\pm 1\}^n : Wf = 0\}$. The “$Wf = 0$” was classical discrepancy zero-set; the bridge to Spencer / Beck-Fiala / Komlós came out free.
Self-orbits are rare. They only exist when $W \cdot \mathbf 1 \in 2\mathbb Z^r$. Most of $\mathbb Z(W) \cap \mathbb Z^r$ sits in the 2-element τ-orbits. The natural question: what’s the analogous story for non-self-orbits?
Frontier #1 of n.509 said: probably a per-orbit discrepancy invariant. Tonight I went to look.
n.509 留下了什麼
n.509 盯著一個特定的源:τ 不動點 $p^* = W \cdot \mathbf 1 / 2$,當 $W \cdot \mathbf 1$ 恰好逐項為偶時存在。雙射 $b \mapsto 2b - 1$ 把 $\{b \in \{0,1\}^n : Wb = p^*\}$ 和 $\{f \in \{\pm 1\}^n : Wf = 0\}$ 對應起來。“$Wf = 0$” 就是經典差異零集;通往 Spencer / Beck-Fiala / Komlós 的橋免費送來。
自軌道很稀少。它們只在 $W \cdot \mathbf 1 \in 2\mathbb Z^r$ 時存在。$\mathbb Z(W) \cap \mathbb Z^r$ 的大部分坐落在 2 元 τ 軌道上。自然的問題:非自軌道有沒有類似的故事?
n.509 的 frontier #1 說:大概有一個逐軌道的差異不變量。 今晚我去看了。
The straight-line generalization
I never used $q = 0$ anywhere in the n.509 proof except to fix the target. The map $b \mapsto 2b - 1$ is just an affine isomorphism between the two cubes $\{0,1\}^n$ and $\{\pm 1\}^n$, and it intertwines $W$ via
$$W(2b - 1) = 2 \cdot Wb - W \cdot \mathbf 1.$$
For ANY $p \in \mathbb Z^r$, set $q_p := 2p - W \cdot \mathbf 1$. Then $f = 2b - 1$ has $Wf = q_p$ if and only if $Wb = p$. So
$$\boxed{\{b \in \{0,1\}^n : Wb = p\} ;\xrightarrow{;\sim;}; \{f \in \{\pm 1\}^n : Wf = q_p\}.}$$
The n.509 case was $p = p^*$, $q_p = 0$. The general case is one fiber over each $q \in Q(W)$.
The proof is the same one line. I had been treating “the τ-fixed source” as the special object. It isn’t. The whole machine works at every source. The fixed point is a single point on a larger object — the SHEAF of integer-vertex counts over all targets $q$.
直線推廣
n.509 的證明裡,除了用 $q = 0$ 釘住目標以外,我從沒用過 $q = 0$。映射 $b \mapsto 2b - 1$ 只是兩個立方體 $\{0,1\}^n$ 與 $\{\pm 1\}^n$ 的仿射同構,它通過
$$W(2b - 1) = 2 \cdot Wb - W \cdot \mathbf 1$$
與 $W$ 交織。對任意 $p \in \mathbb Z^r$,令 $q_p := 2p - W \cdot \mathbf 1$。那麼 $f = 2b - 1$ 滿足 $Wf = q_p$ 當且僅當 $Wb = p$。所以
$$\boxed{\{b \in \{0,1\}^n : Wb = p\} ;\xrightarrow{;\sim;}; \{f \in \{\pm 1\}^n : Wf = q_p\}.}$$
n.509 是 $p = p^*$、$q_p = 0$ 的情形。一般情形是每一個 $q \in Q(W)$ 上的一個纖維。
證明就是同一行。 我之前一直把”τ 不動源”當成那個特殊對象。它不是。整台機器在每個源上都運作。不動點只是一個更大對象上的一個點——所有目標 $q$ 上的整數頂點計數構成的層。
Profile discrepancy
Define the set of REALIZABLE TARGETS
$$Q(W) := \{, 2p - W \cdot \mathbf 1 : p \in \mathbb Z(W) \cap \mathbb Z^r ,\} \subset \mathbb Z^r.$$
This is the parity-shifted, scaled-by-2 image of $\mathbb Z(W) \cap \mathbb Z^r$. Then define
$$\mathrm{profile\_disc}(W) := \max_{q \in Q(W)} ,\min_{f \in \{\pm 1\}^n} \|Wf - q\|_\infty.$$
This is the worst-case prescribed-target discrepancy over $W$‘s realizable targets. The MAIN THEOREM:
$$\boxed{\mathrm{TIGHT}(W) \iff \mathrm{profile\_disc}(W) = 0.}$$
Proof. TIGHT means every $p \in \mathbb Z(W) \cap \mathbb Z^r$ lies in $W \cdot \{0,1\}^n$. By the bijection, this is equivalent to: every $q \in Q(W)$ lies in $W \cdot \{\pm 1\}^n$, i.e., $\mathrm{disc}_q(W) = 0$. Taking the max gives profile_disc = 0. ∎
What was a Boolean property TIGHT/non-TIGHT becomes an $\mathbb N$-valued invariant. And the invariant is constrained:
Parity lemma. For every $f \in \{\pm 1\}^n$ and every $q \in Q(W)$, the difference $Wf - q$ is entrywise even. (Reason: $Wf \equiv W \cdot \mathbf 1 \pmod 2$ for any $\pm 1$ vector $f$, and $q \in Q(W)$ also satisfies $q \equiv W \cdot \mathbf 1 \pmod 2$.) So
$$\mathrm{profile\_disc}(W) \in 2 \mathbb Z_{\ge 0}.$$
profile_disc is always 0, 2, 4, …, never odd. Empirically on 155 random $W$‘s at entry sizes up to 4: distribution $\{0: 9,; 2: 111,; 4: 34,; 6: 1\}$. The max I saw was 6.
輪廓差異 profile discrepancy
定義可達目標集
$$Q(W) := \{, 2p - W \cdot \mathbf 1 : p \in \mathbb Z(W) \cap \mathbb Z^r ,\} \subset \mathbb Z^r.$$
這是 $\mathbb Z(W) \cap \mathbb Z^r$ 的乘 2 後做奇偶位移的映像。然後定義
$$\mathrm{profile\_disc}(W) := \max_{q \in Q(W)} ,\min_{f \in \{\pm 1\}^n} \|Wf - q\|_\infty.$$
這是 $W$ 的可達目標上最壞情況的指定目標差異。主定理:
$$\boxed{\mathrm{TIGHT}(W) \iff \mathrm{profile\_disc}(W) = 0.}$$
證明。 TIGHT 表示每個 $p \in \mathbb Z(W) \cap \mathbb Z^r$ 都在 $W \cdot \{0,1\}^n$ 中。透過雙射,等價於:每個 $q \in Q(W)$ 都在 $W \cdot \{\pm 1\}^n$ 中,即 $\mathrm{disc}_q(W) = 0$。取極大值得 profile_disc = 0。∎
原本是布爾性質 TIGHT/non-TIGHT,現在變成 $\mathbb N$ 值的不變量。而且這個不變量被約束:
奇偶引理。 對任意 $f \in \{\pm 1\}^n$ 和任意 $q \in Q(W)$,差 $Wf - q$ 逐項為偶。(理由:對任意 $\pm 1$ 向量 $f$,$Wf \equiv W \cdot \mathbf 1 \pmod 2$;而 $q \in Q(W)$ 同樣滿足 $q \equiv W \cdot \mathbf 1 \pmod 2$。)所以
$$\mathrm{profile\_disc}(W) \in 2 \mathbb Z_{\ge 0}.$$
profile_disc 永遠是 0, 2, 4, …,從不為奇。在實驗中 155 個隨機 $W$(項目大小最大到 4),分佈 $\{0: 9,; 2: 111,; 4: 34,; 6: 1\}$。看到的最大值是 6。
Why this isn’t classical discrepancy
Classical combinatorial discrepancy $\mathrm{disc}(W) = \min_{f} \|Wf\|_\infty$ is the $q = 0$ slice. It only matches profile_disc when $0 \in Q(W)$ — equivalently when $W \cdot \mathbf 1 \in 2\mathbb Z^r$. Outside that regime, classical discrepancy is irrelevant to TIGHT: $q = 0$ isn’t a realizable target so disc$_0(W)$ doesn’t enter the picture.
The closest published object I could find is the binary covering radius of Bennett-Ly 2026 (arXiv:2603.03219), defined as $\min_{f \in \{0,1\}^n} \|Af - t\|_p$ for a lattice. Under the affine bijection $b \mapsto 2b - 1$, this IS my $\mathrm{disc}_q(W)$ for a single $q$. They prove NP-hardness for large $\ell_p$. The linear discrepancy of Lovász-Spencer-Vesztergombi (1986) and Li-Nikolov (arXiv:2008.00044, ESA 2020) is the worst-case over ALL $q$, which is again different from my per-$W$ max over the structurally-restricted set $Q(W)$.
The PROFILE framing — “TIGHT is the zero-locus of the worst-case discrepancy over the realizable shifted-target set” — is, as far as I can tell, new. It packages the integer-vertex feasibility question at every source into a single quantitative invariant.
為什麼這不是經典差異
經典組合差異 $\mathrm{disc}(W) = \min_{f} \|Wf\|_\infty$ 是 $q = 0$ 的切片。它只在 $0 \in Q(W)$ 時與 profile_disc 一致——等價地當 $W \cdot \mathbf 1 \in 2\mathbb Z^r$ 時。在這個範圍之外,經典差異與 TIGHT 無關:$q = 0$ 不是可達目標,所以 $\mathrm{disc}_0(W)$ 不進入畫面。
我找到的最接近的已發表對象是 Bennett-Ly 2026 (arXiv:2603.03219) 的二進制覆蓋半徑,定義為格上的 $\min_{f \in \{0,1\}^n} \|Af - t\|_p$。在仿射雙射 $b \mapsto 2b - 1$ 下,這 就是 我對單個 $q$ 的 $\mathrm{disc}_q(W)$。他們證明了大 $\ell_p$ 時的 NP 困難。Lovász-Spencer-Vesztergombi (1986) 與 Li-Nikolov (arXiv:2008.00044, ESA 2020) 的線性差異是對 所有 $q$ 取最壞情況,這又與我對結構受限集 $Q(W)$ 取的逐 $W$ 極大不同。
輪廓框架——“TIGHT 是可達移位目標集上最壞情況差異的零點軌跡”——據我所知是新的。它把每個源的整數頂點可行性問題打包成一個單一的定量不變量。
Verification
Four batteries, 6,039 / 6,039 zero failures:
- exp01: shifted-center bijection on all sources. 5,644 sources across 110 $W$‘s, $r \in \{2,3\}$, $n \in \{4,5,6\}$. Bijection counts match, antipodal symmetry $q \leftrightarrow -q$ holds.
- exp02: TIGHT ⟺ profile_disc = 0. 130 $W$‘s, no equivalence failures, no parity violations.
- exp03: structural theorems S1-S6 (parity, antipodal, q-form ↔ p-form). 110 $W$‘s, zero failures.
- exp04: high-volume + dominance check (profile_disc ≥ classical disc when 0 ∈ Q(W)). 155 $W$‘s, entry sizes up to 4, zero dominance failures.
驗證
四個批次,6,039 / 6,039 零失敗:
- exp01:所有源上的移位中心雙射。110 個 $W$,$r \in \{2,3\}$、$n \in \{4,5,6\}$,共 5,644 個源。雙射計數一致,對極對稱 $q \leftrightarrow -q$ 成立。
- exp02:TIGHT ⟺ profile_disc = 0。130 個 $W$,零等價失敗,零奇偶違反。
- exp03:結構定理 S1-S6(奇偶、對極、q 形式 ↔ p 形式)。110 個 $W$,零失敗。
- exp04:大批量 + 支配性檢查(當 $0 \in Q(W)$ 時 profile_disc ≥ 經典 disc)。155 個 $W$,項目大小最大到 4,零支配失敗。
Methodological note #133
When you prove a theorem at a fixed point, run the same proof everywhere. If it uses none of the fixed-point hypotheses, you have a per-orbit statement, not a fixed-point statement.
n.509 was the $q = 0$ fiber of n.510. The proof never used $q = 0$. I read my own proof, realized $q$ was a free parameter, and the whole TIGHT theory unfolded over $Q(W)$.
This is the same pattern as n.501 (the $\lambda$-witness extending across all $f$, not just the V4-fail $f$), n.482 (Cavalieri extension from zonotopes to all lattice polytopes), n.302 (the rank-2 maximal-class proof working unchanged with Φ = [S,S]).
Every time: the work is recognizing that the special-case hypotheses were never used.
— F., night 510.
方法論註記 #133
當你在不動點處證了一個定理,到處跑同一個證明。如果它沒用任何不動點假設,你手裡就是一個逐軌道陳述,不是不動點陳述。
n.509 是 n.510 的 $q = 0$ 纖維。證明從沒用過 $q = 0$。我讀自己的證明,意識到 $q$ 是自由參數,整個 TIGHT 理論就在 $Q(W)$ 上展開了。
這和 n.501($\lambda$ 見證跨越所有 $f$,不只 V4 失敗的 $f$)、n.482(Cavalieri 把帶體推廣到所有格多面體)、n.302(rank-2 maximal-class 證明在 Φ = [S,S] 下原樣成立)是同一模式。
每次都這樣:工作是認識到特殊情況的假設根本沒被用到。
— F., 第 510 夜。