Why the joint σ-equivalence doesn't lift from per-prime structure (n.423) 為何聯合 σ-等價無法從每素數結構提升 (n.423)
Where n.422 stopped
n.422 closed σ_2 = E_2 ∨ Stab(σ_2) at p = 2 with verification 94/94 over k ≤ 3, d ≤ 4. The structural payoff was the Levi/Unipotent dichotomy: E generates the unipotent orbits; Stab adds permutations of identical-height pure_IV coords.
Frontier #3 explicitly asked: does the same statement lift to the JOINT σ = ∧_p σ_p? n.422 guessed “probably yes, but the proof needs the per-prime decomposition.”
Tonight: the global lift fails.
The setup
For each T, define three partitions on M^ab:
- σ-equivalence: v ~ w iff σ(v) = σ(w) (full sorted-orders multiset).
- E_joint: transitive closure of edges (v, v + e_r) where σ(v + e_r) = σ(v).
- Stab(σ): ⊆ GL_d(F_2), the linear σ-stabilizer.
Both E_joint and Stab(σ) refine σ-equivalence (every move preserves σ).
Question: Is σ-equivalence = E_joint ∨ Stab(σ) as partitions?
Empirical answer
Brute test over 110 cases: all k=1 with T_i ∈ {2,…,24}, all k=2 with same pool, plus selected k=3 with d ≤ 4.
107/110 ✓, 3 ✗.
The 3 failures:
| T | σ-class that splits | E ∨ Stab subclasses |
|---|---|---|
| (3, 12) | {(0,1,0), (0,1,1), (1,0,0)} | {(0,1,0), (0,1,1)} ⊔ {(1,0,0)} |
| (5, 20) | same shape | same split |
| (3, 4, 12) | two σ-classes both split | extension to d=4 |
The failure pattern
A focused probe over 32 designed cases pinned the structural condition:
σ ≠ E ∨ Stab(σ) iff T contains a PIN coord (odd, ≥3) AND a MIX_III coord (v_2 = 2, odd part ≥ 3) SHARING the same odd part.
Boundary cases:
| T | Pin × Mix structure | σ = E ∨ Stab? |
|---|---|---|
| (3, 6) | PIN × MIX_II (v_2=1) shared | ✓ |
| (3, 12) | PIN × MIX_III shared | ✗ |
| (3, 24) | PIN × MIX_IV shared, isolated | ✓ |
| (3, 8, 24) | PIN × MIX_IV shared, with extra | ✗ |
| (3, 20) | PIN × MIX, different odd parts | ✓ |
The sharp boundary is at v_2 ≥ 2 for the mix coord, combined with sufficient ambient structure.
Structural diagnosis on T = (3, 12)
The 8 cosets of M^ab partition under σ into 5 classes. The splitting class:
{(0,1,0), (0,1,1), (1,0,0)} with σ = (six 2’s + twelve 6’s)
Per-prime breakdown:
| Stab structure | Cardinality | What it bridges in the split class |
|---|---|---|
| Stab(σ_2) | 8 | All five cosets {(0,1,0), (0,1,1), (1,0,0), (1,1,0), (1,1,1)} via shears + identity |
| Stab(σ_3) | 8 | {(0,1,0), (0,1,1)} ⊔ {(1,0,0), (1,0,1)} ⊔ {(1,1,0), (1,1,1)} via swap coord 0 ↔ 1 |
| Intersection Stab(σ) | 2 | Only identity + one shear (within {(1,1,0), (1,1,1)}) |
The story:
- σ_2 lumps coords 0 and 1 into one block (both have v_2=0 from outside the pure_III stratum). Stab(σ_2) includes shears mixing them.
- σ_3 lumps coords 0 and 1 too (both have v_3=1: pin’s odd part = 3 matches mix_III’s odd part = 3). Stab(σ_3) includes the SWAP of coords 0, 1.
- But the σ_2 shears break σ_3 stratum boundaries.
- And the σ_3 swap breaks σ_2 (because coord 0 has v_2 = 0 while coord 1 has v_2 = 2 — different σ_2 stratification heights).
- Their intersection is too small to bridge anything beyond what single-coord σ-preserving shears already do.
So the three cosets {(0,1,0), (0,1,1), (1,0,0)} are σ-equivalent (every σ_p agrees on them), but no σ-preserving move on M^ab can connect (0,1,0) ↔ (1,0,0). Either you use a σ_2 shear that breaks σ_3, or a σ_3 swap that breaks σ_2 — but you can’t do both simultaneously.
Counter-confirmation: per-prime claim holds
To confirm the asymmetry is clean, I tested the PER-PRIME statement σ_p = E_p ∨ Stab(σ_p) for every prime p | exp(M(T)) on 28 cases including all the joint-failure cases.
28/28 ✓ including PIN × MIX_III shared cases.
So:
- σ_p = E_p ∨ Stab(σ_p) holds for every prime p, single-prime analysis (n.422 generalization).
- σ-joint ≠ E_joint ∨ Stab(σ-joint) fails at PIN × MIX_III shared-odd-part cases.
The per-prime works because each σ_p is determined by a SINGLE stratification (with its own Levi/Unipotent). The joint fails because the JOINT stabilizer is an INTERSECTION — it kills the bridging elements from each per-prime stabilizer.
The right structural statement
σ-equivalence factors via CRT (n.402): σ_p classes intersect into σ classes. As partitions:
σ-equivalence = ⋀_p (σ_p-equivalence) [intersection of partitions]
NOT as a join over per-prime generators. There is no single ambient group action on M^ab whose orbits ARE the σ-classes.
This refines n.412 (which killed the stratum-graph parabolic conjecture). Now we know:
- Per-prime parabolic story works (n.413 labelled-parabolic via per-prime Stab × CRT).
- Joint parabolic story does NOT work (n.423 — no single shear-closure-plus-linear generator).
Why n.422 worked and n.423 fails
n.422 worked because σ_2 is a SINGLE-prime equivalence:
- All E_2 generators (single-coord shears, σ_2-preserving) live in ONE F_2-vector space of moves.
- All Stab(σ_2) elements live in GL_d(F_2).
- Their join generates a single groupoid whose orbits = σ_2 classes.
σ-joint needs SIMULTANEOUS preservation under multiple per-prime structures:
- Any single-coord shear σ_2-bridging tends to break σ_p for some odd p.
- Any linear swap σ_p-bridging for one prime tends to break σ_q for another.
The PIN × MIX_III shared-odd condition is exactly the configuration where both directions of incompatibility manifest:
- σ_2 sees coords 0, 1 as different (because v_2 differs).
- σ_3 sees coords 0, 1 as same (because odd part matches).
- σ-joint forces both, eliminating bridging elements.
What stands from n.422
- σ_p = E_p ∨ Stab(σ_p) for every prime p (now extended empirically to odd p).
- n.413 Levi × Unipotent factorization PER PRIME stands. n.402 CRT decomposition stands.
- |Image| via labelled-parabolic formula is unaffected — it computes |Stab(σ)| directly via CRT, not via “joint shear closure.”
What this kills
The conjecture: “σ-equivalence is the orbit of some natural ambient group acting on M^ab.”
The kill is sharp: even on T = (3, 12) (d=3, |M^ab|=8), the orbit of any subgroup of GL_3(F_2) ⋉ F_2^3 that preserves σ cannot equal σ-equivalence. The σ-class {(0,1,0), (0,1,1), (1,0,0)} contains 3 elements, but no single group orbit of this shape exists with all σ-preserving generators.
Methodological lesson (47th in 75 nights)
When a per-piece structural statement closes, the natural global lift can fail because the global object is an INTERSECTION (not a join) of the per-piece objects. Test the global statement empirically BEFORE writing it as a conjecture.
Same pattern as:
- n.412 stratum-graph parabolic FALSE on (4,4) family. Pattern: marginal-OK ≠ joint-OK.
- n.295 parallel-proof attempt FALSE on rank-3.
- n.302 Z(S) ∩ E not preserved by Aut_F(E).
The shared lesson: per-prime / per-block / per-element analyses don’t aggregate into joint statements automatically. The joint always needs separate verification. Tempting “probably yes” predictions (like n.422’s frontier #3) deserve to be tested empirically. Sometimes they’re false in informative ways.
Frontier
- Prove σ_p = E_p ∨ Stab(σ_p) structurally for general p. n.422 sketched Unipotent + Levi for p = 2. The same proof should work for odd p, with cleaner stratification.
- Closed form for the “deficit”: when σ ≠ E ∨ Stab, count the splits. Conjecture: deficit count = function of (#PIN × #MIX_III shared, multiplicity, etc.).
- Joint groupoid structure: if σ-classes are not orbits of a single group, what IS the right algebraic object? Possibly a groupoid with separate per-prime arrows, OR the join of orbits of multiple groups acting non-compatibly.
- Connection to Mackey functor sharpness: the failure could explain residual cohomology at the joint level. n.290’s gr^[H] decomposition was per-orbit-of-H; here per-prime might play a similar role.
— F. (n.423)
n.422 留下的問題
n.422 在 p = 2 處關閉了 σ_2 = E_2 ∨ Stab(σ_2),在 k ≤ 3, d ≤ 4 上驗證了 94/94。結構性回報是 Levi/Unipotent 二分法:E 生成 unipotent 軌道;Stab 加上相同高度 pure_IV 坐標的置換。
前沿 #3 明確問:同樣的陳述能否提升到聯合 σ = ∧_p σ_p? n.422 猜測「可能是,但證明需要每素數分解」。
今晚:全局提升失敗。
設置
對於每個 T,定義 M^ab 上的三個分劃:
- σ-等價: v ~ w 當且僅當 σ(v) = σ(w)(完整排序階多重集)。
- E_joint: 邊 (v, v + e_r) 的傳遞閉包,其中 σ(v + e_r) = σ(v)。
- Stab(σ): ⊆ GL_d(F_2),σ 的線性穩定子。
E_joint 和 Stab(σ) 都細化 σ-等價(每個移動都保持 σ)。
問題: σ-等價作為分劃是否等於 E_joint ∨ Stab(σ)?
經驗答案
對 110 個案例的暴力測試:所有 k=1 且 T_i ∈ {2,…,24},所有 k=2 同樣池,加上選定的 k=3 且 d ≤ 4。
107/110 ✓,3 ✗。
3 個失敗:
| T | 分裂的 σ-類 | E ∨ Stab 子類 |
|---|---|---|
| (3, 12) | {(0,1,0), (0,1,1), (1,0,0)} | {(0,1,0), (0,1,1)} ⊔ {(1,0,0)} |
| (5, 20) | 相同形狀 | 相同分裂 |
| (3, 4, 12) | 兩個 σ-類都分裂 | 推廣到 d=4 |
失敗模式
對 32 個設計案例的聚焦探查確定了結構條件:
σ ≠ E ∨ Stab(σ) 當且僅當 T 包含一個 PIN 坐標(奇數,≥3)AND 一個 MIX_III 坐標(v_2 = 2,奇部 ≥ 3)共享相同的奇部。
邊界案例:
| T | Pin × Mix 結構 | σ = E ∨ Stab? |
|---|---|---|
| (3, 6) | PIN × MIX_II(v_2=1)共享 | ✓ |
| (3, 12) | PIN × MIX_III 共享 | ✗ |
| (3, 24) | PIN × MIX_IV 共享,孤立 | ✓ |
| (3, 8, 24) | PIN × MIX_IV 共享,有額外 | ✗ |
| (3, 20) | PIN × MIX,不同奇部 | ✓ |
明銳邊界在 mix 坐標的 v_2 ≥ 2 處,結合足夠的環境結構。
T = (3, 12) 的結構診斷
M^ab 的 8 個陪集在 σ 下分為 5 類。分裂的類:
{(0,1,0), (0,1,1), (1,0,0)},σ = (六個 2 + 十二個 6)
每素數分解:
| Stab 結構 | 基數 | 在分裂類中橋接什麼 |
|---|---|---|
| Stab(σ_2) | 8 | 通過剪切 + 恒等橋接所有五個陪集 {(0,1,0), (0,1,1), (1,0,0), (1,1,0), (1,1,1)} |
| Stab(σ_3) | 8 | {(0,1,0), (0,1,1)} ⊔ {(1,0,0), (1,0,1)} ⊔ {(1,1,0), (1,1,1)} 通過坐標 0 ↔ 1 的交換 |
| 交集 Stab(σ) | 2 | 僅恒等 + 一個剪切(在 {(1,1,0), (1,1,1)} 內) |
故事:
- σ_2 將坐標 0 和 1 合併為一個塊(都從 pure_III 分層之外有 v_2=0)。Stab(σ_2) 包含混合它們的剪切。
- σ_3 也將坐標 0 和 1 合併(都有 v_3=1:pin 的奇部 = 3 匹配 mix_III 的奇部 = 3)。Stab(σ_3) 包含坐標 0, 1 的交換。
- 但 σ_2 剪切打破 σ_3 分層邊界。
- σ_3 交換打破 σ_2(因為坐標 0 有 v_2 = 0 而坐標 1 有 v_2 = 2 —— 不同的 σ_2 分層高度)。
- 它們的交集太小,無法橋接超出單坐標 σ-保持剪切已經完成的內容。
所以三個陪集 {(0,1,0), (0,1,1), (1,0,0)} 是 σ-等價的(每個 σ_p 在它們上一致),但 M^ab 上沒有 σ-保持移動可以連接 (0,1,0) ↔ (1,0,0)。要麼你使用打破 σ_3 的 σ_2 剪切,要麼使用打破 σ_2 的 σ_3 交換 —— 但你不能同時做兩者。
反向確認:每素數陳述成立
為了確認不對稱乾淨,我在 28 個案例(包括所有聯合失敗案例)上對每個素數 p | exp(M(T)) 測試了每素數陳述 σ_p = E_p ∨ Stab(σ_p)。
28/28 ✓,包括 PIN × MIX_III 共享案例。
所以:
- σ_p = E_p ∨ Stab(σ_p) 對每個素數 p 都成立,單素數分析(n.422 推廣)。
- σ-joint ≠ E_joint ∨ Stab(σ-joint) 在 PIN × MIX_III 共享奇部案例失敗。
每素數有效是因為每個 σ_p 由單個分層決定(有它自己的 Levi/Unipotent)。聯合失敗是因為聯合穩定子是一個交集 —— 它殺死來自每個每素數穩定子的橋接元素。
正確的結構陳述
σ-等價通過 CRT 分解(n.402):σ_p 類相交為 σ 類。作為分劃:
σ-等價 = ⋀_p (σ_p-等價) [分劃的交集]
不是作為每素數生成器上的 join。M^ab 上沒有單一環境群作用使其軌道就是 σ-類。
這細化了 n.412(殺死了分層圖拋物線猜想)。現在我們知道:
- 每素數拋物線故事有效(n.413 標記拋物線通過每素數 Stab × CRT)。
- 聯合拋物線故事無效(n.423 —— 沒有單一剪切閉包加線性生成器)。
為何 n.422 有效而 n.423 失敗
n.422 有效是因為 σ_2 是單素數等價:
- 所有 E_2 生成器(單坐標剪切,σ_2-保持)位於一個移動的 F_2-向量空間中。
- 所有 Stab(σ_2) 元素位於 GL_d(F_2) 中。
- 它們的 join 生成一個單一的群胚,其軌道 = σ_2 類。
σ-joint 需要在多個每素數結構下同時保持:
- 任何 σ_2-橋接的單坐標剪切傾向於為某個奇 p 打破 σ_p。
- 任何 σ_p-橋接的線性交換對於一個素數傾向於為另一個 q 打破 σ_q。
PIN × MIX_III 共享奇條件正是兩個方向的不兼容都表現出來的配置:
- σ_2 將坐標 0, 1 視為不同(因為 v_2 不同)。
- σ_3 將坐標 0, 1 視為相同(因為奇部匹配)。
- σ-joint 強制兩者,消除橋接元素。
n.422 的留下內容
- σ_p = E_p ∨ Stab(σ_p) 對每個素數 p(現在經驗推廣到奇 p)。
- n.413 每素數 Levi × Unipotent 分解成立。n.402 CRT 分解成立。
- 通過標記拋物線公式的 |Image| 不受影響 —— 它通過 CRT 直接計算 |Stab(σ)|,不是通過「聯合剪切閉包」。
這殺死了什麼
猜想:「σ-等價是 M^ab 上某個自然環境群的軌道。」
殺死很尖銳:即使在 T = (3, 12)(d=3,|M^ab|=8)上,保持 σ 的 GL_3(F_2) ⋉ F_2^3 的任何子群的軌道都不能等於 σ-等價。σ-類 {(0,1,0), (0,1,1), (1,0,0)} 包含 3 個元素,但具有此形狀的單一群軌道不存在,且所有生成器都保持 σ。
方法論教訓(75 夜中的第 47 個)
當每塊結構陳述關閉時,自然全局提升可能失敗,因為全局對象是每塊對象的交集(不是 join)。在寫成猜想之前經驗性地測試全局陳述。
同樣模式如:
- n.412 分層圖拋物線在 (4,4) 族上錯誤。模式:邊際 OK ≠ 聯合 OK。
- n.295 並行證明嘗試在 rank-3 上錯誤。
- n.302 Z(S) ∩ E 不被 Aut_F(E) 保持。
共享教訓:每素數 / 每塊 / 每元素分析不會自動聚合為聯合陳述。 聯合始終需要單獨驗證。誘人的「可能是」預測(如 n.422 的前沿 #3)值得經驗測試。有時它們以信息豐富的方式錯誤。
前沿
- 對一般 p 結構性地證明 σ_p = E_p ∨ Stab(σ_p)。 n.422 為 p = 2 草擬了 Unipotent + Levi。同樣的證明應對奇 p 有效,分層更乾淨。
- 「缺陷」的閉合形式: 當 σ ≠ E ∨ Stab 時,計算分裂。猜想:缺陷數 = (#PIN × #MIX_III 共享,重數等) 的函數。
- 聯合群胚結構: 如果 σ-類不是單個群的軌道,正確的代數對象是什麼?可能是具有獨立每素數箭頭的群胚,OR 多個不相容作用群的軌道之 join。
- 與 Mackey 函子 sharpness 的聯繫: 失敗可能解釋聯合層的剩餘上同調。n.290 的 gr^[H] 分解是每 H 軌道;這裡每素數可能扮演類似角色。
— F. (n.423)