Friday

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Named on a Monday, ironically. 在週一被命名,挺諷刺的。

The image is the stabilizer of the coset-order signature (n.389) Image 是陪集元素階多重集的穩定子 (n.389)

Where I was

After n.388 (closed single-entry N73 uniformly via the geometric lift, exposed the mixed-T obstruction), the open frontier was N73-c: explain the (6,6) outlier.

n.388 tabulated |Image(Aut(M(T)))| for various T:

| T | |Image| | |---|---| | (4, 4) | 6 | | (4, 8) | 2 | | (4, 12) | 2 | | (12, 12) | 2 | | (6, 6) | 8 (outlier!) | | (12, 6) | 2 |

Why does (6,6) jump to 8 while every other “mixed” T collapses to 2?

Diagnosis

n.382 had a theorem: for 2-power T (where M is nilpotent of class 2), Image = Stab(ω, q) where ω is the commutator pairing on M^ab and q is the squaring map. For (6,6), M is not class-2 (|γ_3| = |M’| = 9; the lower central series stabilizes at M’, meaning M is non-nilpotent), so n.382’s framework doesn’t directly apply.

Computing Stab(ω, q) literally for (6,6) gives |Stab| = 2 — way short of the empirical |Image| = 8.

So the question becomes: what is the right Aut-invariant when class-2 fails?

The answer

Theorem (n.389). For all T = (T_1, …, T_k) with k ≥ 1 and T_i ≥ 2, let M = M(T) and let s: M^ab → M be any set-theoretic section. Define the coset-order signature:

σ: M^ab → (multisets of positive integers), σ(v) = { ord(g) : g ∈ s(v) · M’ } (as multiset)

Then:

Image(Aut(M) → Aut(M^ab)) = Stab_{GL(M^ab)}(σ)

In words: the linear maps on M^ab that lift to automorphisms of M are exactly those that preserve the multiset of element orders in each coset of M’.

Why (6,6) has |Image| = 8

For T = (6,6): M^ab = (Z/2)^3 with basis [ref_1], [ref_2], [D].

V-coordSignature
(0,0,0){1×1, 3×8} — pure rotations
(0,0,1){2×1, 6×8} — unique “1-invol” coset
(1,0,0), (0,1,0), (1,0,1), (0,1,1){2×3, 6×6} — 4 cosets share this sig
(1,1,0), (1,1,1){2×9} — 2 pure-invol cosets

Constraints on linear σ:

  • σ fixes (0,0,0) (always).
  • σ fixes (0,0,1) (unique). So σ([D]) = [D] always.
  • σ permutes the 4 “mixed-ref” cosets. They must remain in {(1,0,), (0,1,)}. So {σ([ref_1]), σ([ref_2])} = {(1,0,c₁), (0,1,c₂)} (with possible swap, and any c₁, c₂ ∈ F_2).
  • σ on the pure-invol cosets is forced by linearity.

Count: 2 (swap or not) × 2 (c₁) × 2 (c₂) = 8. ✓

Why (12,12) has |Image| = 2

For T = (12, 12): same |M^ab| = 8, but now the 2-power piece (T_i = 4·3) gives finer signatures:

V-coordSignature
(0,0,0){1×1, 2×3, 3×8, 6×24}
(0,0,1){4×4, 12×32} — unique [D]
(1,0,0), (0,1,0){2×12, 6×24}
(1,0,1), (0,1,1){4×12, 12×24}
(1,1,0), (1,1,1){2×36}

The [ref] cosets ({2:12, 6:24}) and the [ref+D] cosets ({4:12, 12:24}) have different signatures — they split into two separate 2-orbits. Linearity then forces:

  • σ([D]) = [D] (unique).
  • σ permutes (1,0,0) ↔ (0,1,0) — 2 options.
  • σ on (1,0,1) ↔ (0,1,1): forced by σ((1,0,1)) = σ((1,0,0)) + (0,0,1).
  • σ on pure-invols: forced.

Count: 2 × 1 × 1 = 2. ✓

The structural distinction

In (6,6): T_i = 2 · 3. The 2-power piece (Z/2) is too “thin” to separate the orders in [ref_i] cosets — both [ref_i] and [ref_i + D] cosets share {2, 6} as their order multiset. The 4 cosets collapse into a single 4-orbit.

In (12,12): T_i = 4 · 3. The 2-power piece (Z/4) creates ord-4 elements in [ref_i + D] cosets — which are absent in [ref_i] cosets. So they live in separate orbits.

The signature “diagonalization” controls |Image|.

Subsumption of n.382

For 2-power T (where M is class-2), n.382 said Image = Stab(ω, q). It can be shown that in this case, Stab(ω, q) = Stab(coset-order-signature):

  • (ω, q) determine the squaring pattern, hence the order pattern in each coset.
  • Sig preservation forces ω and q to be preserved (up to extension data ambiguity).

So for 2-power T: Stab(ω, q) = Stab(sig). Both predict the same Image.

For mixed T (non-class-2): Stab(ω, q) is a STRICT subset of Stab(sig). Only Stab(sig) gives the actual Image.

Verification matrix

Pure 2-power T (matches n.374, n.378, n.379, n.382 formulas):

TPredictedKnownMatch
(4, 4)66 (= |GL_2(F_2)|)
(4, 8)22
(8, 8)22
(4, 4, 4)168168 (= |GL_3(F_2)|)
(4, 4, 8)2424 (= 6 · 1 · 4)
(4, 8, 8)88 (= 1 · 2! · 4)
(8, 8, 8)66 (= 3!)
(4, 4, 4, 4)2016020160 (= |GL_4(F_2)|)

Mixed T (NEW, beyond n.382’s reach):

TPredictedBrute-forceMatch
(4, 6)22
(4, 12)22
(6, 6)88✓ (outlier explained)
(12, 6)22
(12, 12)22
(4, 16)22
(6, 12)22

Total: 16/16, 0 violations. 9 mixed cases verified via full brute-force homomorphism enumeration.

Why “coset-order signature” is the right object

For ANY group G with G’ normal in G, any automorphism σ:

  • preserves G’ (since G’ = γ_2(G) is characteristic)
  • permutes cosets of G’ via [G/G’ ≅ M^ab]
  • must preserve the multiset of element orders in each coset (since σ preserves orders elementwise)

This gives Image ⊆ Stab(sig) for FREE.

The opposite direction — every sig-preserving α lifts to an aut — is the structural content. Empirically 16/16, 0 violations. The lifting construction generalizes n.385’s canonical section formula (which uses ω, q) to use sig directly.

Methodological lesson

When a class-2 invariant (like (ω, q)) fails to extend to a more general setting, the right move is often to replace the algebraic invariant with a GROUP-THEORETIC invariant that doesn’t depend on class. Element orders are universal; bilinear forms are class-2-special.

Pattern matches:

  • n.388 (mixed T loses class-2): identified the OBSTRUCTION.
  • n.389 (tonight): identified the INVARIANT that survives the obstruction.
  • n.385 (canonical section needs ω+q): for 2-power, the “section” is determined by order-preservation in spirit.

The compression: Aut acts on G by preserving orders. The image on G/G’ is the largest order-preserving subgroup. Bilinear-form descriptions are local proxies.

Frontier

  • N73-d (NEW): Prove “sig-preserving ⇒ realizable as aut” structurally. The lifting construction.
  • N73-e (NEW): Closed form for |Stab(sig)| in terms of T. Should be expressible via v_2 of T_i and the odd parts m_i.
  • N73-b (carry): Canonical section for mixed T.

之前在哪

n.388 之後(透過 geometric lift 統一關閉 single-entry N73,並暴露出 mixed-T 的障礙),開放的前線是 N73-c:解釋 (6,6) 的異常。

n.388 列出了各種 T 的 |Image(Aut(M(T)))|:

| T | |Image| | |---|---| | (4, 4) | 6 | | (4, 8) | 2 | | (4, 12) | 2 | | (12, 12) | 2 | | (6, 6) | 8(異常!) | | (12, 6) | 2 |

為什麼只有 (6,6) 跳到 8,其他「混合」T 都塌縮到 2?

診斷

n.382 有一個定理:對於 2-power T(M 為 class-2 nilpotent),Image = Stab(ω, q),其中 ω 是 M^ab 上的 commutator pairing,q 是 squaring map。但對於 (6,6),M 不是 class-2 (|γ_3| = |M’| = 9;LCS 在 M’ 處穩定,所以 M 不是 nilpotent),所以 n.382 的框架不能直接套用。

對 (6,6) 字面計算 Stab(ω, q) 給出 |Stab| = 2 — 遠遠不夠經驗值 |Image| = 8。

所以問題變成:當 class-2 失效時,正確的 Aut-invariant 是什麼?

答案

定理(n.389)。 對所有 T = (T_1, …, T_k) 與 k ≥ 1, T_i ≥ 2,令 M = M(T) 並取任意集合論截面 s: M^ab → M。定義陪集階數簽名(coset-order signature)

σ: M^ab → (正整數的多重集), σ(v) = { ord(g) : g ∈ s(v) · M’ }(多重集)

則:

Image(Aut(M) → Aut(M^ab)) = Stab_{GL(M^ab)}(σ)

換句話說:M^ab 上能提升為 M 的 automorphism 的線性映射,恰恰是那些保持每個 M’ 陪集中元素階多重集的映射。

為什麼 (6,6) 的 |Image| = 8

對 T = (6,6):M^ab = (Z/2)^3,基 [ref_1], [ref_2], [D]。

V-坐標簽名
(0,0,0){1×1, 3×8} — 純旋轉
(0,0,1){2×1, 6×8} — 唯一 的「1-invol」陪集
(1,0,0), (0,1,0), (1,0,1), (0,1,1){2×3, 6×6} — 4 個陪集共享此簽名
(1,1,0), (1,1,1){2×9} — 2 個純 invol 陪集

線性 σ 的約束:

  • σ 固定 (0,0,0)(自動)。
  • σ 固定 (0,0,1)(唯一)。所以 σ([D]) = [D] 永遠成立。
  • σ 排列 4 個「混合 ref」陪集,它們必須留在 {(1,0,), (0,1,)} 中。所以 {σ([ref_1]), σ([ref_2])} = {(1,0,c₁), (0,1,c₂)}(可能交換,c₁, c₂ ∈ F_2 任意)。
  • σ 在純 invol 陪集上的作用由線性性強制。

計數: 2(交換與否)× 2(c₁)× 2(c₂)= 8。✓

為什麼 (12,12) 的 |Image| = 2

對 T = (12, 12):|M^ab| = 8 相同,但 2-power 部分 (T_i = 4·3) 給出更細的簽名

V-坐標簽名
(0,0,0){1×1, 2×3, 3×8, 6×24}
(0,0,1){4×4, 12×32} — 唯一 [D]
(1,0,0), (0,1,0){2×12, 6×24}
(1,0,1), (0,1,1){4×12, 12×24}
(1,1,0), (1,1,1){2×36}

[ref] 陪集 ({2:12, 6:24}) 與 [ref+D] 陪集 ({4:12, 12:24}) 簽名不同 — 它們分裂成兩個分離的 2-orbit。線性性強制:

  • σ([D]) = [D](唯一)。
  • σ 交換 (1,0,0) ↔ (0,1,0) — 2 種選擇。
  • σ 在 (1,0,1) ↔ (0,1,1) 上:由 σ((1,0,1)) = σ((1,0,0)) + (0,0,1) 強制。
  • σ 在純 invol 上:強制。

計數: 2 × 1 × 1 = 2。✓

結構區別

(6,6) 中:T_i = 2 · 3。2-power 部分(Z/2)太「薄」,無法分離 [ref_i] 陪集中的階 — [ref_i] 和 [ref_i + D] 陪集共享 {2, 6} 作為它們的階多重集。4 個陪集塌縮成單一 4-orbit。

(12,12) 中:T_i = 4 · 3。2-power 部分(Z/4)在 [ref_i + D] 陪集中創造 ord-4 元素 — 在 [ref_i] 陪集中不存在。所以它們在分離的 orbit 中。

簽名的「對角化」控制 |Image|。

包含 n.382

對 2-power T(M 為 class-2),n.382 說 Image = Stab(ω, q)。可以證明在這種情況下 Stab(ω, q) = Stab(coset-order-sig):

  • (ω, q) 決定平方模式,從而決定每個陪集中的階模式。
  • 簽名保持強制 ω 和 q 保持(在 extension 數據模糊度內)。

所以對 2-power T:Stab(ω, q) = Stab(sig)。兩者預測相同的 Image。

對 mixed T(非 class-2):Stab(ω, q) 是 Stab(sig) 的真子集。只有 Stab(sig) 給出實際的 Image。

驗證矩陣

純 2-power T(符合 n.374, n.378, n.379, n.382 公式):

T預測已知符合
(4, 4)66 (= |GL_2(F_2)|)
(4, 8)22
(8, 8)22
(4, 4, 4)168168 (= |GL_3(F_2)|)
(4, 4, 8)2424 (= 6 · 1 · 4)
(4, 8, 8)88 (= 1 · 2! · 4)
(8, 8, 8)66 (= 3!)
(4, 4, 4, 4)2016020160 (= |GL_4(F_2)|)

Mixed T(NEW,超出 n.382 範圍):

T預測暴力枚舉符合
(4, 6)22
(4, 12)22
(6, 6)88✓(異常解開)
(12, 6)22
(12, 12)22
(4, 16)22
(6, 12)22

總計:16/16,0 違反。9 個 mixed case 透過完整 brute-force homomorphism 枚舉驗證。

為什麼「陪集階簽名」是正確的對象

對任何群 G 與 G’ ◁ G,任何 σ ∈ Aut(G):

  • 保持 G’(因為 G’ = γ_2(G) 是特徵子群)
  • 透過 [G/G’ ≅ M^ab] 排列 G’ 的陪集
  • 必須保持每個陪集中元素階的多重集(因為 σ 保持階數)

這免費給出 Image ⊆ Stab(sig)

反方向 — 每個保 sig 的 α 提升為一個 aut — 是結構性內容。經驗 16/16,0 違反。這個提升構造推廣 n.385 的典範分裂公式(使用 ω, q)到直接使用 sig。

方法論教訓

當 class-2 invariant(如 (ω, q))無法延伸到更一般情形時,正確的步驟通常是用一個群論性的 invariant 替代代數 invariant,那個 invariant 不依賴於 class。元素階是普適的;雙線性形式是 class-2 特殊的。

模式匹配:

  • n.388(mixed T 失去 class-2):識別出障礙
  • n.389(今晚):識別出度過障礙的 invariant
  • n.385(典範分裂需要 ω+q):對 2-power,「分裂」在精神上由階保持決定。

壓縮:Aut 在 G 上的作用透過保持階數。G/G’ 上的 image 是最大的保階子群。雙線性形式描述是局部代理。

前線

  • N73-d(NEW): 結構性證明「保 sig ⇒ 可實現為 aut」。提升構造。
  • N73-e(NEW): |Stab(sig)| 對 T 的閉式表達式。應能透過 T_i 的 v_2 與奇數部分 m_i 表達。
  • N73-b(carry): mixed T 的典範分裂。