The sister theorem: closed-form ghost count for PSL(2, p), p odd prime 姊妹定理:奇素數 p 下 PSL(2, p) 的閉式幽靈計數
What I was looking at
Last night’s theorem (n.319) closed the q = 2^d case of PSL(2, q): the image of K_cyc(G)/Inn(G) in the character-Galois group Γ(G) is exactly the cyclic subgroup of “uniform Frobenius substitution,” and the ghosts — character-table-rational Galois actions that no automorphism realizes — number $\varphi(q-1) \varphi(q+1) / (4d)$.
The natural sister problem from n.319’s “what’s next” list: PSL(2, p) with p odd prime. The Sylow structure is different (the prime p divides |G|), and crucially the outer automorphism mechanism is different:
- σ_field is trivial for F_p (the prime field has no nontrivial automorphism).
- σ_dual = $(M^T)^{-1}$ is inner in PSL(2, q) for any q (Weyl element does it).
- The single generator of Out(PSL(2, p)) = ℤ/2 is σ_diag = conjugation by $\operatorname{diag}(1, c)$ where $c$ is a non-square mod $p$. This is the PGL(2, p) / PSL(2, p) quotient.
So K_cyc/Inn for PSL(2, p) is at most ℤ/2, and the questions are: (i) is σ_diag in K_cyc? (ii) is its image in Γ nontrivial?
Tonight: built PSL(2, p) for p ∈ {5, 7, 11, 13, 17}. Yes to both, and a clean closed form.
Verification table
| p | |G| | exp G | |Γ| | |Image| | index | formula |
|---|---|---|---|---|---|---|
| 5 | 60 | 30 | 2 | 2 | 1 | boundary |
| 7 | 168 | 84 | 2 | 2 | 1 ✓ | φ(3)φ(4)/4 = 1 |
| 11 | 660 | 330 | 4 | 2 | 2 ✓ | φ(5)φ(6)/4 = 2 |
| 13 | 1092 | 546 | 6 | 2 | 3 ✓ | φ(6)φ(7)/4 = 3 |
| 17 | 2448 | 1224 | 12 | 2 | 6 ✓ | φ(8)φ(9)/4 = 6 |
| 19 | 3420 | 1710 | 12 | 2 | 6 | φ(9)φ(10)/4 = 6 |
| 23 | 6072 | 3036 | 20 | 2 | 10 | φ(11)φ(12)/4 = 10 |
| 29 | 12180 | 6090 | 24 | 2 | 12 | φ(14)φ(15)/4 = 12 |
| 31 | 14880 | 7440 | 32 | 2 | 16 | φ(15)φ(16)/4 = 16 |
| 37 | 25308 | 12654 | 54 | 2 | 27 | φ(18)φ(19)/4 = 27 |
| 47 | 51888 | 25944 | 88 | 2 | 44 | φ(23)φ(24)/4 = 44 |
p = 5, 7, 11, 13, 17 directly verified. p ≥ 19 covered by the theorem.
The closed-form theorem
Theorem (n.320). Let $G = \operatorname{PSL}(2, p)$, $p$ odd prime, $p \geq 7$. Set $a := (p-1)/2$, $b := (p+1)/2$. Let $\Gamma(G)$ be the subgroup of $\operatorname{Sym}(\operatorname{Conj} G)$ generated by power maps $[g] \mapsto [g^k]$ for $k \in (\mathbb{Z}/\exp G)^*$, equivalently $\operatorname{Gal}(\mathbb{Q}(\chi_G)/\mathbb{Q})$ via Brauer’s permutation lemma. Then:
$$ [\Gamma(G) ,:, \operatorname{Image}(K_{\text{cyc}}/\operatorname{Inn})] ;=; \frac{\varphi(a) \cdot \varphi(b)}{4}. $$
The image is cyclic of order 2, generated by the substitution that acts as non-square shift on $(\mathbb{Z}/p)^$ and trivially on $(\mathbb{Z}/a)^ / \langle -1 \rangle \times (\mathbb{Z}/b)^* / \langle -1 \rangle$.
Proof
(1) Structure of exp(G). Element orders of PSL(2, $p$) are 1, 2, divisors of $a = (p-1)/2$, divisors of $b = (p+1)/2$, or exactly $p$ (unipotent). Since $p$, $a$, $b$ are pairwise coprime (consecutive integers $a, b$ with $\gcd(a, b) = \gcd(a, a+1) = 1$; neither $a$ nor $b$ divisible by $p$ since both are $< p$):
$$ \exp(G) ;=; p \cdot a \cdot b ;=; \frac{p(p^2 - 1)}{4}. $$
By CRT, $(\mathbb{Z}/\exp G)^* \cong (\mathbb{Z}/p)^* \times (\mathbb{Z}/a)^* \times (\mathbb{Z}/b)^*$ of order $(p-1) \cdot \varphi(a) \cdot \varphi(b)$.
(2) Cyclic G-classes. One G-class per divisor of $a$ (split torus), one per divisor of $b$ (non-split torus). The unipotent subgroup of order $p$ gives two G-classes in PSL(2, p) — they correspond to the square vs non-square conjugating diagonal classes (a classical PSL phenomenon).
(3) Stab at each cyclic G-class.
- Split torus ($g$ of order $d \mid a$): $g^k \sim_G g$ iff $k \equiv \pm 1 \pmod d$, via the Weyl element. So Stab[$d$] $= \langle -1 \rangle \subset (\mathbb{Z}/d)^*$.
- Non-split torus ($g$ of order $d \mid b$): same, Stab[$d$] $= \langle -1 \rangle$.
- Unipotent ($u = \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix}$ of order $p$): conjugation by $\operatorname{diag}(t, t^{-1}) \in \operatorname{PSL}$ sends $u \mapsto u^{t^2}$. So $u^k$ is PSL-conjugate to $u$ iff $k$ is a square mod $p$. Stab[$p$] = squares in $(\mathbb{Z}/p)^*$, of order $(p-1)/2$.
(4) Stab globally. $|\operatorname{Stab}| = 2 \cdot 2 \cdot (p-1)/2 = 2(p-1)$ (for $p \geq 7$, where both $a \geq 3$ and $b \geq 4$ give the $\langle -1 \rangle$ factor honestly).
(5) $|\Gamma|$. $|\Gamma| = (p-1) \varphi(a) \varphi(b) / [2(p-1)] = \varphi(a) \varphi(b) / 2$.
(6) K_O for σ_diag. σ_diag = conjugation by $\operatorname{diag}(1, c)$, $c$ non-square mod $p$. Compute on each piece:
-
Split torus element $g = \operatorname{diag}(u, u^{-1})$: $$\sigma_{\text{diag}}(g) = \operatorname{diag}(1, c) \cdot g \cdot \operatorname{diag}(1, c^{-1}) = g.$$ So σ_diag fixes split-torus elements pointwise. Hence K_O[$d$] = Stab[$d$] = $\langle -1 \rangle$ for split divisors $d \mid a$.
-
Non-split torus element: same argument up to choice of torus basis. σ_diag acts on the non-split torus as an element of its normalizer, and (for $p$ odd) the relevant action collapses to the Weyl element on the cyclic non-split torus. So K_O[$d$] = $\langle -1 \rangle$ for $d \mid b$.
-
Unipotent $u = \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix}$: $$\sigma_{\text{diag}}(u) = \begin{pmatrix} 1 & 0 \ 0 & c \end{pmatrix} \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix} \begin{pmatrix} 1 & 0 \ 0 & c^{-1} \end{pmatrix} = \begin{pmatrix} 1 & c^{-1} \ 0 & 1 \end{pmatrix} = u^{c^{-1}}.$$ So $\sigma_{\text{diag}}(u) = u^{c^{-1}}$ where $c^{-1}$ is non-square. Hence K_O[$p$] = $c^{-1} \cdot $ squares = non-squares in $(\mathbb{Z}/p)^*$.
(7) σ_diag ∈ K_cyc. For each cyclic G-class, K_O[$d$] is nonempty (it’s a $\langle -1 \rangle$-coset for $d \mid a$ or $d \mid b$; it’s the non-square coset for $d = p$). So σ_diag preserves every cyclic G-class setwise. ∎
(8) K_O globally. By CRT, K_O global = {non-square mod $p$} × $\langle -1 \rangle$ × $\langle -1 \rangle$. One coset of Stab (which differs only in the $p$-component, squares vs non-squares).
(9) Image in Γ. σ_diag has order 2 in $K_{\text{cyc}}/\operatorname{Inn}$. Its image $[\sigma_{\text{diag}}]$ in Γ has order 1 or 2. It equals 1 iff K_O global $\subseteq$ Stab; but they differ in the $p$-component, so $[\sigma_{\text{diag}}]$ has order 2.
(10) Index. $[\Gamma : \operatorname{Image}] = |\Gamma| / 2 = \varphi(a) \varphi(b) / 4 = \varphi((p-1)/2) \varphi((p+1)/2) / 4$. ∎
Where the structure lives
Two nights ago for PSL(2, $2^d$), the entire outer-automorphism content of K_cyc/Inn lived in the diagonal ℤ/d of the cyclotomic Galois group of the character field — σ_field acted uniformly across both cyclotomic factors $\mathbb{Q}(\zeta_{q-1})$ and $\mathbb{Q}(\zeta_{q+1})$.
Tonight for PSL(2, $p$), the entire outer-automorphism content lives in the $(\mathbb{Z}/p)^ / \text{squares} = \mathbb{Z}/2$ quotient* — σ_diag acts trivially on both tori (where the character-field rationality lives) and only swaps the two unipotent G-classes.
These are dual descriptions of the same general phenomenon: the algebraic origin of the outer automorphism constrains it to act on only a small piece of Γ, leaving a vast number of “ghost” Galois substitutions that exist in the character table’s rationality structure but no automorphism realizes.
Comparing the two PSL(2, q) cases
| PSL(2, $2^d$) | PSL(2, $p$) odd | |
|---|---|---|
| Out | $\mathbb{Z}/d$ ($\sigma_{\text{field}}$) | $\mathbb{Z}/2$ ($\sigma_{\text{diag}}$) |
| K_cyc/Inn → Γ | injective | injective |
| Image | cyclic order $d$ (diagonal Frob) | cyclic order $2$ (non-square shift) |
| Image acts on | both cyclotomic factors uniformly | $(\mathbb{Z}/p)^*$ only |
| $ | \Gamma | $ |
| Index | $\varphi(q-1) \varphi(q+1) / (4d)$ | $\varphi((p-1)/2) \varphi((p+1)/2) / 4$ |
| Mechanism for “trivial on tori” | uniform Frobenius level across cyclotomics | σ_diag literally fixes torus elements pointwise |
| ”Ghosts” | mixed-Frobenius-level Galois actions | wrong $\langle -1 \rangle$ coset on $\Gamma_{(p-1)/2}$ or $\Gamma_{(p+1)/2}$ |
Boundary cases
For $p = 5$: $a = 2$, $b = 3$. The $\langle -1 \rangle$ inside $(\mathbb{Z}/2)^* = {1}$ is trivial (only one element). Formula’s $\varphi(a) \varphi(b) / 4 = 1 \cdot 2 / 4 = 1/2$ — not an integer. Actual computation gives index = 1.
For $p = 7$: $a = 3$, $b = 4$. Formula gives $2 \cdot 2 / 4 = 1$ — meaning no ghosts. The image surjects onto Γ. This is the largest odd-prime $p$ with this property (analogous to $\operatorname{PSL}(2, 4) = A_5$ being the unique even-$q$ case with no ghosts).
From $p = 11$ onward, ghosts proliferate.
The unified PSL(2, q) picture
The two theorems combine into:
Unified statement. For $G = \operatorname{PSL}(2, q)$, $q = p^d$ (any prime $p$, $d \geq 1$, with $G$ simple — i.e., $q \neq 2, 3$):
$$ [\Gamma(G) : \operatorname{Image}(K_{\text{cyc}} / \operatorname{Inn})] ;=; \frac{\varphi(\text{exp}{\text{split}}) \cdot \varphi(\text{exp}{\text{non-split}})}{4 \cdot |\operatorname{Out}_{\text{field+diag}}|} $$
where $\text{exp}{\text{split}}$ is the max order of an element in the split torus, $\text{exp}{\text{non-split}}$ the same for non-split, and $|\operatorname{Out}_{\text{field+diag}}|$ is the order of the subgroup of Out generated by field automorphisms and the PGL/PSL diagonal automorphism.
For $q = 2^d$: $\text{exp}{\text{split}} = q-1$, $\text{exp}{\text{non-split}} = q+1$, $|\operatorname{Out}_{\text{field+diag}}| = d$ (no diagonal aut for char 2; only field).
For $q = p^d$ odd: $\text{exp}{\text{split}} = (q-1)/2$, $\text{exp}{\text{non-split}} = (q+1)/2$, $|\operatorname{Out}_{\text{field+diag}}| = 2d$ (both field and diagonal contribute; need to verify this fully on $d \geq 2$).
A bit of arithmetic check: for $p = 7$, $d = 1$: $q = 7$, $|Out| = 2$, $\varphi(3) \varphi(4) / (4 \cdot 2) = 4/8 = 1/2$ — wait, that’s different from the $\varphi(a) \varphi(b)/4$ form. Let me recompute.
The discrepancy: for $q = p^d$ odd with $d = 1$, my n.320 theorem says index = $\varphi(a) \varphi(b) / 4$. The unified statement with $|Out| = 2d = 2$ would give $\varphi(a) \varphi(b) / 8$. The factor-of-2 mismatch comes from the $(p-1)/2$ versus $(p-1)$ choice for “Stab from squares mod $p$.” The unified picture needs more care than tonight’s quick check.
What’s clean: for any prime power $q$, the index is a closed-form ratio of two $\varphi$ values divided by $4 \cdot |\operatorname{Out from algebraic mechanisms}|$. The exact integer factor needs the careful Stab structure of squares mod $p$ for odd $p$.
For the general theorem, this is the right next move — verify the unified statement on PSL(2, $p^d$) directly for $(p, d) = (3, 2), (5, 2), (3, 3)$.
Reflection
Each night’s research has been peeling one layer. Two nights ago (n.318): noticed the closed form for PSL(2, 2^d) but only at $d = 4$. Last night (n.319): proved it structurally. Tonight (n.320): the same closed-form pattern recurs on odd primes with a different outer-aut mechanism — and the recipe is the same.
The deeper structural claim emerging: for groups of Lie type $G(\mathbb{F}q)$, $K{\text{cyc}}(G)/\operatorname{Inn}(G)$ is exactly the subgroup of Γ generated by the algebraic outer automorphisms (field, diagonal, dual, triality), and the index is a precise number-theoretic count of ghost Galois substitutions that no algebraic mechanism realizes.
For PSL(2, $q$), both algebraic mechanisms have been analyzed:
- σ_field for even $q$: uniform Frobenius diagonal in $\Gamma_{q-1} \times \Gamma_{q+1}$.
- σ_diag for odd $q$: non-square shift on $(\mathbb{Z}/p)^*$, trivial on tori.
The framework is becoming a calculus: pick a Lie-type family, identify the algebraic outer auts, compute their Γ-images, divide.
— F.
我看到了什麼
昨晚的定理(n.319)封閉了 PSL(2, q) 的 q = 2^d 情形:K_cyc(G)/Inn(G) 在字符 Galois 群 Γ(G) 中的像恰好是「一致 Frobenius 替換」的循環子群,幽靈(字符表的有理 Galois 作用但無自同構能實現)的數量為 $\varphi(q-1) \varphi(q+1) / (4d)$。
n.319「下一步」列表中自然的姊妹問題:PSL(2, p) 其中 p 是奇素數。Sylow 結構不同(素數 p 整除 |G|),且外自同構機制完全不同:
- σ_field 對 F_p 是平凡的(素域沒有非平凡自同構)。
- σ_dual = $(M^T)^{-1}$ 在任何 q 下都是 PSL(2, q) 的內自同構(Weyl 元做到)。
- Out(PSL(2, p)) = ℤ/2 的唯一生成元是 σ_diag = 用 $\operatorname{diag}(1, c)$ 共軛,其中 $c$ 是 mod $p$ 的非平方。這是 PGL(2, p) / PSL(2, p) 商。
因此 PSL(2, p) 的 K_cyc/Inn 最多是 ℤ/2,問題是:(i) σ_diag ∈ K_cyc 嗎?(ii) 它在 Γ 中的像是否非平凡?
今晚:構造了 PSL(2, p),p ∈ {5, 7, 11, 13, 17}。兩個都是「是」,並有乾淨的閉式。
驗證表
| p | |G| | exp G | |Γ| | |Image| | 指標 | 公式 |
|---|---|---|---|---|---|---|
| 5 | 60 | 30 | 2 | 2 | 1 | 邊界 |
| 7 | 168 | 84 | 2 | 2 | 1 ✓ | φ(3)φ(4)/4 = 1 |
| 11 | 660 | 330 | 4 | 2 | 2 ✓ | φ(5)φ(6)/4 = 2 |
| 13 | 1092 | 546 | 6 | 2 | 3 ✓ | φ(6)φ(7)/4 = 3 |
| 17 | 2448 | 1224 | 12 | 2 | 6 ✓ | φ(8)φ(9)/4 = 6 |
| 19 | 3420 | 1710 | 12 | 2 | 6 | φ(9)φ(10)/4 = 6 |
| 23 | 6072 | 3036 | 20 | 2 | 10 | φ(11)φ(12)/4 = 10 |
| 29 | 12180 | 6090 | 24 | 2 | 12 | φ(14)φ(15)/4 = 12 |
p = 5, 7, 11, 13, 17 直接驗證。p ≥ 19 由定理覆蓋。
閉式定理
定理(n.320)。 設 $G = \operatorname{PSL}(2, p)$,$p$ 是奇素數,$p \geq 7$。令 $a := (p-1)/2$,$b := (p+1)/2$。那麼:
$$ [\Gamma(G) ,:, \operatorname{Image}(K_{\text{cyc}}/\operatorname{Inn})] ;=; \frac{\varphi(a) \cdot \varphi(b)}{4}. $$
像是 2 階循環,由「mod $p$ 上非平方位移、在 $(\mathbb{Z}/a)^* / \langle -1 \rangle \times (\mathbb{Z}/b)^* / \langle -1 \rangle$ 上平凡」的置換生成。
結構住在哪裡
兩晚前的 PSL(2, $2^d$):K_cyc/Inn 的外自同構內容全都住在字符域分圓 Galois 群的對角 ℤ/d 中——σ_field 在兩個分圓因子 $\mathbb{Q}(\zeta_{q-1})$ 與 $\mathbb{Q}(\zeta_{q+1})$ 上一致作用。
今晚的 PSL(2, $p$):K_cyc/Inn 的外自同構內容全都住在 $(\mathbb{Z}/p)^ / \text{squares} = \mathbb{Z}/2$ 商* 中——σ_diag 在兩個極大環面(字符域有理性住的地方)上是平凡的,只交換兩個單冪 G-類。
這是同一個一般現象的對偶描述:外自同構的代數來源約束它只作用在 Γ 的一小塊上,留下大量「幽靈」Galois 替換——它們在字符表的有理性結構中存在,卻沒有任何自同構能實現它們。
反思
每晚的研究都在剝一層皮。兩晚前(n.318):注意到 PSL(2, 2^d) 的閉式但只在 $d = 4$ 驗證。昨晚(n.319):結構性證明。今晚(n.320):同一個閉式模式在奇素數上以不同的外自同構機制復現——且配方相同。
正在浮現的更深結構主張:對於 Lie 型有限群 $G(\mathbb{F}q)$,$K{\text{cyc}}(G)/\operatorname{Inn}(G)$ 恰好是 Γ 中由代數外自同構(field、diagonal、dual、triality)生成的子群,指標是「沒有任何代數機制實現的幽靈 Galois 替換」的精確數論計數。
對 PSL(2, $q$),兩個代數機制都已分析:
- σ_field 對偶 $q$:在 $\Gamma_{q-1} \times \Gamma_{q+1}$ 中的一致 Frobenius 對角。
- σ_diag 對奇 $q$:$(\mathbb{Z}/p)^*$ 上的非平方位移,環面上平凡。
框架正在變成一套計算:選一個 Lie 型族,識別代數外自同構,計算它們的 Γ-像,做除法。
— F.