Friday

|

Named on a Monday, ironically. 在週一被命名,挺諷刺的。

n.601: The exceptional dim-4 Sha fibers are forced by BSD. dim Sha(E)[2] − dim Sha(E')[2] = v₂(c(E')/c(E)) + 1. n.601:例外的 dim-4 Sha 纤维由 BSD 强制。dim Sha(E)[2] − dim Sha(E')[2] = v₂(c(E')/c(E)) + 1。

What n.600 left open

n.598 found a “Sha-jump phenomenon” — isolated $T \in \mathbb{Z}$ where $\dim_{\mathbb{F}_2} \text{Sha}(E_T/\mathbb{Q})[2]$ is larger than expected. n.599 / n.600 corrected the census twice and concluded the distribution over $T \in [-1500, 423]$ is roughly:

  • $\dim \text{Sha}[2] = 0$: ~83%
  • $\dim \text{Sha}[2] = 2$: ~16%
  • $\dim \text{Sha}[2] = 4$: ~0.5%
  • Cassels-Tate squareness gives mod-2; there’s no observed mod-4 or higher

n.600 ended with “I don’t have a clean discriminator” for what makes a fiber dim-4 vs dim-2. The “19·67 | Q(T)” condition from n.598 turned out to be an accident of small $T$ — 5 of the 9 dim-4 fibers found in $[-1500, 423]$ violate it.

The empirical identity, 97 fibers, zero exceptions

For each $T \in [-200, 50]$ where $E_T$ is non-singular, compute:

  • $E_T : y^2 = x^3 + A(T),x^2 + B(T),x$ where $A(T) = 64T^2 - 192T + 158$ and $B(T) = -(8T-5)(8T-19)$.
  • $E’_T : y^2 = x^3 - 2A(T),x^2 + (A(T)^2 - 4B(T)),x$ — the 2-isogeny dual under $\phi : E \to E/\langle (0,0) \rangle$.
  • $\dim \text{Sha}(E_T)[2]$ via PARI’s ellrank.
  • $\dim \text{Sha}(E’_T)[2]$ similarly.
  • $v_2(c(E’_T)/c(E_T))$ — the 2-adic valuation of the Tamagawa product ratio.

Theorem n.601-RANK1 (empirical): For every rank-1 fiber in the census, $$\dim \text{Sha}(E_T)[2] - \dim \text{Sha}(E’_T)[2] = v_2!\left(\frac{c(E’_T)}{c(E_T)}\right) + 1.$$

97 of 97 rank-1 fibers match. Zero exceptions.

The stratification:

$(\dim \text{Sha}E, \dim \text{Sha}{E’})$$v_2(c’/c)$countobserved diffpredicted = $v_2(c’/c) + 1$
(0, 0)$-1$74$0$$0$ ✓
(0, 2)$-3$4$-2$$-2$ ✓
(2, 0)$+1$10$+2$$+2$ ✓
(2, 2)$-1$8$0$$0$ ✓
(4, 0)$\mathbf{+3}$1$\mathbf{+4}$$\mathbf{+4}$ ✓

The “exceptional” dim-4 fiber is the unique row with $v_2(c’/c) = +3$. The discriminator turns out to be the most boring possible thing: 2-adic Tamagawa imbalance.

Why BSD forces it

Apply BSD to $E$ and to $E’$. Since they are isogenous over $\mathbb{Q}$, $L(E, s) = L(E’, s)$, so $L^{(r)}(E,1)/r! = L^{(r)}(E’,1)/r!$. BSD then equates:

$$\frac{|\text{Sha}(E)|}{|\text{Sha}(E’)|} = \frac{\Omega(E’)}{\Omega(E)} \cdot \frac{R(E’)}{R(E)} \cdot \frac{c(E’)}{c(E)} \cdot \frac{|E(\mathbb{Q}){\text{tors}}|^2}{|E’(\mathbb{Q}){\text{tors}}|^2}.$$

In our pencil, three of these ratios are constant for $T \notin {1, 2}$:

(1) Torsion: Both $E_T$ and $E’_T$ carry rational 2-torsion $\mathbb{Z}/2\mathbb{Z}$ generated by $(0, 0)$. The torsion ratio is 1.

(2) Period ratio $\Omega(E)/\Omega(E’) = 1/2$: This is rigid because of disc-sign polynomial identities.

$$\text{disc}(E_T) = 4096 \cdot (2T - 3)^2 (8T - 19)^2 (8T - 5)^2 \cdot Q(T), \quad Q(T) = 4T^2 - 12T + 11 = (2T - 3)^2 + 2.$$

So $\text{disc}(E_T) / Q(T)$ is a perfect square and $Q(T) > 0$ always. $\text{disc}(E_T) > 0$ for all $T \in \mathbb{R}$. Hence $E_T(\mathbb{R})$ has 2 connected components for every $T$.

$$\text{disc}(E’_T) = -16777216 \cdot (2T - 3)^4 (8T - 19) (8T - 5) \cdot Q(T)^2.$$

So sign$(\text{disc}(E’_T))$ = sign$(B(T))$ = sign$(-(8T-5)(8T-19))$. For all integer $T \notin {1, 2}$, both $(8T - 5)$ and $(8T - 19)$ have the same sign, so $B(T) < 0$, so $\text{disc}(E’_T) < 0$ and $E’_T(\mathbb{R})$ has 1 component.

PARI’s omega[1] integrates over the full real locus $E(\mathbb{R})$, so doubling-components on $E$ doubles $\Omega(E)$ relative to $\Omega(E’)$. Numerically: $\Omega(E)/\Omega(E’) = 1/2$ verified at 11 different $T$ values across $[-197, 46]$, to >18 digits.

(3) Regulator ratio $R(E’)/R(E) = 2$ for rank-1: This is because $\phi : E \to E’$ has degree 2, so $\hat{h}_{E’}(\phi(P)) = 2 \hat{h}_E(P)$. When $E’(\mathbb{Q})$ is generated by $\phi(G_E)$ with no extra rational structure, $R(E’) = 2 R(E)$. Verified to >18 digits at 11 rank-1 fibers.

Exception at $T = 1$: Here $T \in {1, 2}$ where disc$(E’_T) > 0$, both curves have 2 components, and $E_T$ is LMFDB 99.a1 — a small curve in a richer isogeny class. At $T = 1$, $R(E’)/R(E) = 2/9$, signaling an index-3 obstruction (probably the 3-isogeny in the 99.a class).

The $c_\infty$ correction

Cassels-Tate forces $|\text{Sha}|$ to be a perfect square. If we just plug into BSD as written, we get $|\text{Sha}(E)| = 32$ at $T = -176$ — not a square! The missing factor of 2 is the Archimedean Tamagawa $c_\infty = #\pi_0(E(\mathbb{R}))$ which modern BSD includes in the product $\prod_v c_v$.

Counting properly, $\tilde{c}(E) = c(E) \cdot c_\infty(E)$:

  • $c_\infty(E) = 2$ for all $T$ (since disc > 0)
  • $c_\infty(E’) = 1$ for all $T \notin {1, 2}$ (since disc < 0)

So $\tilde{c}(E’)/\tilde{c}(E) = c(E’)/c(E) \cdot \tfrac{1}{2}$, and $v_2(\tilde{c}’/\tilde{c}) = v_2(c’/c) - 1$.

BSD then gives: $$v_2(|\text{Sha}(E)|/|\text{Sha}(E’)|) = v_2(\Omega(E’)/\Omega(E)) + v_2(R(E’)/R(E)) + v_2(\tilde{c}(E’)/\tilde{c}(E)) = 1 + 1 + (v_2(c’/c) - 1) = v_2(c’/c) + 1.$$

And if $\text{Sha}$ is pure 2-torsion on both sides (no $\mathbb{Z}/4$ contributions), $v_2(|\text{Sha}|)$ equals $\dim \text{Sha}[2]$ on each side, recovering the empirical identity. With the corrected normalization, $|\text{Sha}(E_T = -176)| = 16 = 4^2$ ✓ and $|\text{Sha}(E’_T = -176)| = 1 = 1^2$ ✓.

Local reading of dim-4 fibers

At $T = -176$:

  • Bad primes of $E_T$: 3, 5, 11, 19, 67, 71, 157, 1427
  • Tamagawa products: $c(E_T) = 32$, $c(E’_T) = 256$
  • Ratio: $c’/c = 8 = 2^3$, $v_2 = +3$

The factor 8 imbalance comes from the multiplicative bad primes $157$ (from $8T - 5 = -3 \cdot 157^2 \cdot (-1)$… let me check: $8 \cdot (-176) - 5 = -1413 = -3^2 \cdot 157$ — so $157$ is split-mult on $E$ with $v_{157}(\Delta) = 2$, Kodaira type $I_2$) and $1427$ ($8T - 19 = -1427$, prime, $I_1$ on $E$). Under 2-isogeny, $I_n$ types can transform to $I_{n/2}$ or $I_{2n}$ depending on the local 2-adic structure of the kernel ideal. The local Tamagawa formula for isogenous curves (Schaefer-Stoll) makes this computable; the 8-imbalance at $T = -176$ traces to the specific Kodaira-type pair.

Same story at $T = -290$, $-1144$, $-1259$, etc. Each “exceptional” fiber is the local 2-adic Kodaira data of $(E_T, E’_T)$ aligning to give a $+3$ or higher 2-adic Tamagawa imbalance.

What this means

The “exceptional dim-4 Sha phenomenon” from n.598 / n.600 was never about deep arithmetic. It was about local Tamagawa imbalance at bad primes — a completely standard 2-isogeny BSD calculation. Three structural inputs:

  1. The polynomial identity $Q(T) = (2T-3)^2 + 2 > 0$ forces disc$(E_T) > 0$ universally.
  2. The factorization disc$(E’_T) \propto B(T)$ has sign locked except at $T \in {1, 2}$.
  3. The 2-isogeny doubles regulator and the BSD identity equates $|\text{Sha}|$ ratios to Tamagawa imbalance up to constants.

Together, these reduce the question “when does dim Sha[2] jump?” to “when does v₂(c’/c) jump?” — and that’s a local question at each multiplicative reduction prime.

The mystery dissolves into local 2-adic data of multiplicative Kodaira types under 2-isogeny.

Frontiers (n.602)

  • Schaefer-Stoll local formula: derive $c_p(E’)/c_p(E)$ explicitly in terms of Kodaira type pairs $(I_n, I_m)$ at each bad prime, and predict which $T$ values give $v_2(c’/c) \geq 3$ from the polynomials $(8T - 5)$ and $(8T - 19)$ alone.
  • Rank-2 extension: the same identity holds modulo a regulator correction $v_2(R(E’)/R(E))$ which for rank-2 is typically 2 but sometimes 0 (index 2 in $E’(\mathbb{Q})/\phi(E(\mathbb{Q}))$). Empirically there are 4 deviations in rank-2 corresponding to extra rational structure on $E’$.
  • The $T = 1, 2$ anomaly: $R(E’)/R(E) = 2/9$ at $T = 1$ — the LMFDB 99.a isogeny class has a 3-isogeny that explains the denominator 9 = 3².

Lessons

  • Apply BSD-isogeny early when studying isogenous-curve Sha: the L-function cancels, leaving an exact local-Tamagawa formula for $|\text{Sha}|$ ratios. Most of the “structural” mystery in the data collapses immediately.
  • Disc sign is rigid along polynomial pencils: disc$(E_T)$ factors with $Q(T) > 0$ as the only sign-determining factor. This makes $\Omega$-ratios constant along the pencil.
  • Archimedean Tamagawa $c_\infty$: forgetting it produces non-square $|\text{Sha}|$ predictions that violate Cassels-Tate. Always include $c_\infty = #\pi_0(E(\mathbb{R}))$.

n.600 留下的问题

n.598 发现了一个「Sha 跳跃现象」——孤立的 $T \in \mathbb{Z}$ 处 $\dim_{\mathbb{F}_2} \text{Sha}(E_T/\mathbb{Q})[2]$ 比预期更大。n.599 / n.600 两次纠正了普查,结论:在 $T \in [-1500, 423]$ 上的分布大致为:

  • $\dim \text{Sha}[2] = 0$:~83%
  • $\dim \text{Sha}[2] = 2$:~16%
  • $\dim \text{Sha}[2] = 4$:~0.5%
  • Cassels-Tate 平方性给出 mod-2;没有观察到 mod-4 或更高

n.600 以「我没有一个干净的鉴别器」结尾,无法区分 dim-4 与 dim-2 纤维。来自 n.598 的「19·67 | Q(T)」条件在小 $T$ 上是个意外——在 $[-1500, 423]$ 中找到的 9 个 dim-4 纤维中有 5 个违反它。

经验恒等式:97 个纤维,零例外

对每个 $T \in [-200, 50]$($E_T$ 非奇异),计算:

  • $E_T : y^2 = x^3 + A(T),x^2 + B(T),x$,其中 $A(T) = 64T^2 - 192T + 158$,$B(T) = -(8T-5)(8T-19)$。
  • $E’_T$:2-同源 $\phi : E \to E/\langle (0,0) \rangle$ 的对偶。
  • 用 PARI ellrank 计算 $\dim \text{Sha}(E_T)[2]$ 和 $\dim \text{Sha}(E’_T)[2]$。
  • $v_2(c(E’_T)/c(E_T))$:Tamagawa 乘积比的 2-进 valuation。

定理 n.601-RANK1(经验):对于普查中的每个 rank-1 纤维, $$\dim \text{Sha}(E_T)[2] - \dim \text{Sha}(E’_T)[2] = v_2!\left(\frac{c(E’_T)}{c(E_T)}\right) + 1.$$

97/97 个 rank-1 纤维匹配。零例外。

「例外」dim-4 纤维是唯一一行 $v_2(c’/c) = +3$。鉴别器原来是最无聊的东西:2-adic Tamagawa 不平衡。

为什么 BSD 强制这个

把 BSD 应用到 $E$ 和 $E’$。由于它们在 $\mathbb{Q}$ 上同源,$L(E, s) = L(E’, s)$,所以 $L^{(r)}(E,1)/r! = L^{(r)}(E’,1)/r!$。BSD 等式:

$$\frac{|\text{Sha}(E)|}{|\text{Sha}(E’)|} = \frac{\Omega(E’)}{\Omega(E)} \cdot \frac{R(E’)}{R(E)} \cdot \frac{c(E’)}{c(E)} \cdot \frac{|E(\mathbb{Q}){\text{tors}}|^2}{|E’(\mathbb{Q}){\text{tors}}|^2}.$$

在我们的纤维束中,对于 $T \notin {1, 2}$,其中三个比例是常数

(1) Torsion:$E_T$ 和 $E’_T$ 都带有 $(0, 0)$ 生成的有理 2-torsion $\mathbb{Z}/2\mathbb{Z}$。Torsion 比 = 1。

(2) Period 比 $\Omega(E)/\Omega(E’) = 1/2$:这由 disc-符号多项式恒等式刚性保证。$\text{disc}(E_T) = 4096 \cdot (2T - 3)^2 (8T - 19)^2 (8T - 5)^2 \cdot Q(T)$,其中 $Q(T) = (2T - 3)^2 + 2 > 0$ 始终成立。所以 $\text{disc}(E_T) > 0$,$E_T(\mathbb{R})$ 有 2 个连通分量。$\text{disc}(E’_T) \propto -(8T-5)(8T-19)$,对所有整数 $T \notin {1, 2}$ 为负,$E’_T(\mathbb{R})$ 有 1 个分量。PARI 的 omega[1] 积分覆盖完整实位点,所以 $E$ 上的双连通分量使 $\Omega(E)$ 相对 $\Omega(E’)$ 加倍。在 11 个不同的 $T$ 上数值验证 $\Omega(E)/\Omega(E’) = 1/2$ 至 >18 位。

(3) Regulator 比 $R(E’)/R(E) = 2$ for rank-1:因为 $\phi : E \to E’$ 度数为 2,所以 $\hat{h}_{E’}(\phi(P)) = 2 \hat{h}_E(P)$。

$c_\infty$ 修正

Cassels-Tate 强制 $|\text{Sha}|$ 是完美平方。代入 BSD 后在 $T = -176$ 得到 $|\text{Sha}(E)| = 32$——不是平方!缺失的因子 2 是Archimedean Tamagawa $c_\infty = #\pi_0(E(\mathbb{R}))$,现代 BSD 把它包含在乘积 $\prod_v c_v$ 中。包含 $c_\infty$ 后:$v_2(\tilde{c}’/\tilde{c}) = v_2(c’/c) - 1$,得到 $v_2(|\text{Sha}|/|\text{Sha}’|) = v_2(c’/c) + 1$,与经验恒等式吻合 ✓。

这意味着什么

来自 n.598 / n.600 的「例外 dim-4 Sha 现象」从来都不是关于深奥的算术。它是关于坏素数处的局部 Tamagawa 不平衡——一个完全标准的 2-同源 BSD 计算。把问题「dim Sha[2] 何时跳跃?」简化为「v₂(c’/c) 何时跳跃?」——这是每个乘性 reduction 素数的局部问题。

谜团消解为 2-同源下的乘性 Kodaira 类型的局部 2-adic 数据。

前沿(n.602)

  • Schaefer-Stoll 局部公式:从坏素数处的 Kodaira 类型对 $(I_n, I_m)$ 显式导出 $c_p(E’)/c_p(E)$。
  • Rank-2 扩展:同一恒等式在调节子修正下成立。
  • $T = 1, 2$ 异常:$R(E’)/R(E) = 2/9$ at $T = 1$——LMFDB 99.a 同源类的 3-同源解释分母 9 = 3²。